12. Only 25% of reactant A remained after 42 minutes for a certain second-order reaction of A → products at 25°C. What is its rate constant? 6.8 x 10-3 M-1 min-1 O 3.3 x 10-2 M-1 min-1 O 7.9 x 10-2 M1 min-1 O 7.1 x 10-2 M-1 min-1

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Q: - The activation energy for the following 1st-order reaction is 114 kJ/mol. N₂0s (g) → 2 NO₂ (g) +…

A: K2  at temperatureT2(-5°C) = 2.14×10-7 s-1 Explanation:Step 1:.

Q: Time (s) [N205] (M) 0.0365 600 0.0274 2 N205 (aq) → 4 NO2 (aq) + 02(g) 1200 0.0206 1800 0.0157 2400…

A: Recall the given reaction,                     2 N2O5 aq  →  4 NO2 aq  +  O2 gThis is a first…

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Q: Consider the mechanism. Step 1: Step 2: E Overall: A+ D B+E Determine the rate law for the overall…

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Q: This image is a graphical representation of: Slope = k y-intercept = 1/[C]o %3D Time (s) 2nd order…

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Q: Kinetic data at relatively short times for the reaction Colg) + NO 2(g) → CO 2(9) + NO(g) at 120 °C…

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Q: What is the rate constant of a first-order reaction when 20.0% of a reactant remains after 30.0 s?

A: This is first order reaction.For first order reaction, rate law is

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Q: Pure ozone decomposes slowly to oxygen, 203(g)302(g).203(g)-302(g). Determine the order and rate…

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Q: What is the rate constant of a first-order reaction when 20.0% of a reactant remains after 48.0 s?

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Q: [A], M t, s 2.000 1.429 2 1.111 4 5 1.000 0.833 7 0.667 10 0.500 0.333 15 25 0.286 0.250 0.125 30 35…

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Q: What is the rate constant of a first-order reaction when 20.0% of a reactant remains after 30.0 s?

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A: Activation energy= 155 KJ/mol  Initial temperature (T1)= 623 K  Let final temperature= T2

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