12. Look for Relationships Explain how to find the value of b in the equation of a hyperbola, given one focus at (0, 1) and one vertex at (0, 0.5).

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
icon
Related questions
Question

12 please 

### Hyperbolas

#### Definition:
A hyperbola is the set of all points \(P\) such that the difference of the distances from any point \(P\) to two fixed points is constant.

#### Graphs:

**Horizontal Hyperbola:**
- The graph shows a horizontal hyperbola with its transverse axis along the x-axis.
- It has two vertices located at \((\pm a, 0)\).
- Asymptotes are the lines that the hyperbola approaches but never meets. They are shown in blue and have the equations \(y = \pm \frac{b}{a}x\).
- The foci, represented by \(F_1\) and \(F_2\), are located along the x-axis at \((\pm c, 0)\) where \(c = \sqrt{a^2 + b^2}\).

**Vertical Hyperbola:**
- This graph represents a vertical hyperbola with its transverse axis along the y-axis.
- It has two vertices located at \((0, \pm a)\).
- The asymptotes, shown in blue, have the equations \(y = \pm \frac{a}{b}x\).
- The foci, represented by \(F_1\) and \(F_2\), are located along the y-axis at \((0, \pm c)\) where \(c = \sqrt{a^2 + b^2}\).

#### Equation:

**Horizontal:**
\[ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \]
- Vertices: \((\pm a, 0)\)
- Asymptotes: \(y = \pm \frac{b}{a}x\)
- Foci: \((\pm c, 0)\), where \(c = \sqrt{a^2 + b^2}\)

**Vertical:**
\[ \frac{y^2}{a^2} - \frac{x^2}{b^2} = 1 \]
- Vertices: \((0, \pm a)\)
- Asymptotes: \(y = \pm \frac{a}{b}x\)
- Foci: \((0, \pm c)\), where \(c = \sqrt{a^2 + b^2}\)

#### Do You Understand?

1
Transcribed Image Text:### Hyperbolas #### Definition: A hyperbola is the set of all points \(P\) such that the difference of the distances from any point \(P\) to two fixed points is constant. #### Graphs: **Horizontal Hyperbola:** - The graph shows a horizontal hyperbola with its transverse axis along the x-axis. - It has two vertices located at \((\pm a, 0)\). - Asymptotes are the lines that the hyperbola approaches but never meets. They are shown in blue and have the equations \(y = \pm \frac{b}{a}x\). - The foci, represented by \(F_1\) and \(F_2\), are located along the x-axis at \((\pm c, 0)\) where \(c = \sqrt{a^2 + b^2}\). **Vertical Hyperbola:** - This graph represents a vertical hyperbola with its transverse axis along the y-axis. - It has two vertices located at \((0, \pm a)\). - The asymptotes, shown in blue, have the equations \(y = \pm \frac{a}{b}x\). - The foci, represented by \(F_1\) and \(F_2\), are located along the y-axis at \((0, \pm c)\) where \(c = \sqrt{a^2 + b^2}\). #### Equation: **Horizontal:** \[ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \] - Vertices: \((\pm a, 0)\) - Asymptotes: \(y = \pm \frac{b}{a}x\) - Foci: \((\pm c, 0)\), where \(c = \sqrt{a^2 + b^2}\) **Vertical:** \[ \frac{y^2}{a^2} - \frac{x^2}{b^2} = 1 \] - Vertices: \((0, \pm a)\) - Asymptotes: \(y = \pm \frac{a}{b}x\) - Foci: \((0, \pm c)\), where \(c = \sqrt{a^2 + b^2}\) #### Do You Understand? 1
Expert Solution
steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Recommended textbooks for you
Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
Geometry
ISBN:
9781337614085
Author:
Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:
Cengage,
Elementary Geometry for College Students
Elementary Geometry for College Students
Geometry
ISBN:
9781285195698
Author:
Daniel C. Alexander, Geralyn M. Koeberlein
Publisher:
Cengage Learning