12. Let X be the number of successful rocket launches in 629 independent trials with success probability 0.894. Using the binomial distribution, let Q₁ the probability that X > 542, Q₂ the probability that X ≤ 572, and Q3 the probability that 558 < X < 572. Let Q = ln(3 + |Q1| +2|Q2|+3|Q3|). Then T = 5 sin² (100Q) satisfies:- (A) 0 ≤ T < 1. - (B) 1 ≤ T<2. (C) 2 ≤T <3. - (D) 3 ≤ T < 4. — (E) 4 ≤ T ≤ 5.

A First Course in Probability (10th Edition)
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Chapter1: Combinatorial Analysis
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12. Let X be the number of successful rocket launches in 629 independent trials with
success probability 0.894. Using the binomial distribution, let Q₁ the probability that
X ≥ 542, Q₂ the probability that X ≤ 572, and Q3 the probability that 558 ≤X ≤ 572.
Let Q=In(3 + |Q1| +2|Q2|+3|Q3|). Then T = 5 sin² (100Q) satisfies:- (A) 0 ≤T < 1.
(B) 1 ≤ T <2. — (C) 2 ≤T < 3. — (D) 3 ≤ T < 4. (E) 4 ≤ T ≤ 5.
Transcribed Image Text:12. Let X be the number of successful rocket launches in 629 independent trials with success probability 0.894. Using the binomial distribution, let Q₁ the probability that X ≥ 542, Q₂ the probability that X ≤ 572, and Q3 the probability that 558 ≤X ≤ 572. Let Q=In(3 + |Q1| +2|Q2|+3|Q3|). Then T = 5 sin² (100Q) satisfies:- (A) 0 ≤T < 1. (B) 1 ≤ T <2. — (C) 2 ≤T < 3. — (D) 3 ≤ T < 4. (E) 4 ≤ T ≤ 5.
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