12. Let X be the number of successful rocket launches in 629 independent trials with success probability 0.894. Using the binomial distribution, let Q₁ the probability that X > 542, Q₂ the probability that X ≤ 572, and Q3 the probability that 558 < X < 572. Let Q = ln(3 + |Q1| +2|Q2|+3|Q3|). Then T = 5 sin² (100Q) satisfies:- (A) 0 ≤ T < 1. - (B) 1 ≤ T<2. (C) 2 ≤T <3. - (D) 3 ≤ T < 4. — (E) 4 ≤ T ≤ 5.
12. Let X be the number of successful rocket launches in 629 independent trials with success probability 0.894. Using the binomial distribution, let Q₁ the probability that X > 542, Q₂ the probability that X ≤ 572, and Q3 the probability that 558 < X < 572. Let Q = ln(3 + |Q1| +2|Q2|+3|Q3|). Then T = 5 sin² (100Q) satisfies:- (A) 0 ≤ T < 1. - (B) 1 ≤ T<2. (C) 2 ≤T <3. - (D) 3 ≤ T < 4. — (E) 4 ≤ T ≤ 5.
A First Course in Probability (10th Edition)
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ISBN:9780134753119
Author:Sheldon Ross
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Chapter1: Combinatorial Analysis
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Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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![12. Let X be the number of successful rocket launches in 629 independent trials with
success probability 0.894. Using the binomial distribution, let Q₁ the probability that
X ≥ 542, Q₂ the probability that X ≤ 572, and Q3 the probability that 558 ≤X ≤ 572.
Let Q=In(3 + |Q1| +2|Q2|+3|Q3|). Then T = 5 sin² (100Q) satisfies:- (A) 0 ≤T < 1.
(B) 1 ≤ T <2. — (C) 2 ≤T < 3. — (D) 3 ≤ T < 4. (E) 4 ≤ T ≤ 5.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F857d0b74-9920-4062-b169-25d6148d6593%2Febab5a14-cceb-4d50-88fa-46c46546bac8%2Fgkgpe6d_processed.png&w=3840&q=75)
Transcribed Image Text:12. Let X be the number of successful rocket launches in 629 independent trials with
success probability 0.894. Using the binomial distribution, let Q₁ the probability that
X ≥ 542, Q₂ the probability that X ≤ 572, and Q3 the probability that 558 ≤X ≤ 572.
Let Q=In(3 + |Q1| +2|Q2|+3|Q3|). Then T = 5 sin² (100Q) satisfies:- (A) 0 ≤T < 1.
(B) 1 ≤ T <2. — (C) 2 ≤T < 3. — (D) 3 ≤ T < 4. (E) 4 ≤ T ≤ 5.
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