12. Is this reasoning for finding the solutions of the equation V 2x – 1 = X correct? (1) 2x - 1 = X is given; %3D (2) 2x (1); - 1 : x ,obtained by squaring both sides of 2 X - 1 = 0, obtained by subtracting x from both (3) sides of (2); (4) (x – 1) (x + 1) = 0, obtained by factoring the %3D 2 left-hand side of x - 1; -%3B (5) implies that a = 0 or b = 0. X = 1 or X = -1, which follows because ab = 0 %3D
12. Is this reasoning for finding the solutions of the equation V 2x – 1 = X correct? (1) 2x - 1 = X is given; %3D (2) 2x (1); - 1 : x ,obtained by squaring both sides of 2 X - 1 = 0, obtained by subtracting x from both (3) sides of (2); (4) (x – 1) (x + 1) = 0, obtained by factoring the %3D 2 left-hand side of x - 1; -%3B (5) implies that a = 0 or b = 0. X = 1 or X = -1, which follows because ab = 0 %3D
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
![12. Is this reasoning for finding the solutions of the equation
V 2x – 1
= X correct?
(1)
2x - 1 = x is given;
%3D
2x – 1 =
x ,obtained by squaring both sides of
(1);
X - 1 = 0, obtained by subtracting x from both
(3)
sides of (2);
(4)
(x – 1) (x + 1) = 0, obtained by factoring the
%3D
2
left-hand side of x- 1;
-%3B
(5)
X = 1 or X = -1, which follows because ab = 0
%3D
implies that a = 0 or b = 0.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6d68fdca-47e8-4691-a224-b480cf034bf9%2F4e774fac-c325-4916-9dc1-a26736b1489a%2Fca1kfwm_processed.jpeg&w=3840&q=75)
Transcribed Image Text:12. Is this reasoning for finding the solutions of the equation
V 2x – 1
= X correct?
(1)
2x - 1 = x is given;
%3D
2x – 1 =
x ,obtained by squaring both sides of
(1);
X - 1 = 0, obtained by subtracting x from both
(3)
sides of (2);
(4)
(x – 1) (x + 1) = 0, obtained by factoring the
%3D
2
left-hand side of x- 1;
-%3B
(5)
X = 1 or X = -1, which follows because ab = 0
%3D
implies that a = 0 or b = 0.
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