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12. In the given circuit the current I, is 1) 0.4 A 2) - 0.4 A 30 3) 0.8 A 4) - 0.8 A 40 an 40 80

12. In the given circuit the current I, is 1) 0.4 A 2) - 0.4 A 30 3) 0.8 A 4) - 0.8 A 40 an 40 80

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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12. In the given circuit the current I¡ is 19. Two batteries each of emf E and internal resistance r are connected turn by turn in series and in parallel, and are used to find current in an external resistance R. If the current in series is equal to that in parallel, the internal resistance of each battery is: 1) R 2) R/2 20. In the network shown the potential difference between A and B is (R=r,=r2=r3=12, E;=3V, Ez=2V, E3=1V) 1) 1V 2) 2V 3) 3V 4) 4V 21. Consider the circuit shown in the figure. The current I3 is equal to 1) 5 amp 2) 3 amp 3) -3 amp 4) -5/6 amp 22. The potential difference between points A and B adjoining figure is 1) 0.4 A 2) - 0.4 A 30 3) 0.8 A 4) - 0.8 A 40 an. 3) R/3 13. The emf of a battery is 2 V and its internal resistance is 0.5 Q. The maximum power which it can deliver to any external circuit will be 4) R/4 1) 8 Watt 2) 4 Watt 4) None of the above E1 3) 2 Watt 14. A battery is charged at a potential of 15 V for 8 hours when the current flowing is 10 A. The battery on discharge supplies a current of 5 A for 15 hours. The mean terminal voltage during discharge is 14 V. The "Watt-hour" efficiency of the battery is 1) 82.5% 3) 90% 54 2 2) 80 % 4) 87.5% 15. When the resistance of 9 Q is connected at the ends of a battery, its potential difference decreases from 40 volt to 30 volt. The internal resistance of the battery is 1) 6Ω2) 3) 9 04) 16. Two batteries, one of emf 18 volts and internal resistance 22 and the other of emf 12 volt and internal resistance 12, are connected as shown. The voltmeter V will record a reading of 2. 1) 3 50 8. 2) v 9. 32 15 2 sa 4 3) V 4) 2V 3 23. The current in adjoining circuit will be 1) 15 volt 1) ampere 45 2) 30 volt 181202 2) ampere 30 n 4,30 a 3) 14 volt 4) 18 volt 15 1 ampere 10 12112 30 n 17. The n rows each containing m cells in series are joined in parallel. Maximum current is taken from this combination across an external resistance of 32 1 4) ampere 24. The reading of the ammeter as per figure shown resistance. If the total number of cells used are 24 and is internal resistance of each cell is 0.5 2 then 3 1) 2) A 4 1) m = 8, n = 3 2) m = 6,n = 4 2V 3) m = 12,n = 2 4) m = 2,n = 12 3) 4) 2 20 ww 18. The magnitude and direction of the circuit in the circuit shown will be ww 25. A battery of e.m.f 10V is connected to resistance as shown in figure. The potential difference VA-VB between the points A and B is 1) -2V 2) 2 V 3) 5 V 20 1) 7 A from a to b through e 3 7 A from b to a through e 10 "ww iHwb 20 2) 3 10 A 30 ww w 10 V 30 ww 3) 1 A from b to a through e 4) 1 A from a to b through e 4) V 10 V 11 1/81/2
Transcribed Image Text:12. In the given circuit the current I¡ is 19. Two batteries each of emf E and internal resistance r are connected turn by turn in series and in parallel, and are used to find current in an external resistance R. If the current in series is equal to that in parallel, the internal resistance of each battery is: 1) R 2) R/2 20. In the network shown the potential difference between A and B is (R=r,=r2=r3=12, E;=3V, Ez=2V, E3=1V) 1) 1V 2) 2V 3) 3V 4) 4V 21. Consider the circuit shown in the figure. The current I3 is equal to 1) 5 amp 2) 3 amp 3) -3 amp 4) -5/6 amp 22. The potential difference between points A and B adjoining figure is 1) 0.4 A 2) - 0.4 A 30 3) 0.8 A 4) - 0.8 A 40 an. 3) R/3 13. The emf of a battery is 2 V and its internal resistance is 0.5 Q. The maximum power which it can deliver to any external circuit will be 4) R/4 1) 8 Watt 2) 4 Watt 4) None of the above E1 3) 2 Watt 14. A battery is charged at a potential of 15 V for 8 hours when the current flowing is 10 A. The battery on discharge supplies a current of 5 A for 15 hours. The mean terminal voltage during discharge is 14 V. The "Watt-hour" efficiency of the battery is 1) 82.5% 3) 90% 54 2 2) 80 % 4) 87.5% 15. When the resistance of 9 Q is connected at the ends of a battery, its potential difference decreases from 40 volt to 30 volt. The internal resistance of the battery is 1) 6Ω2) 3) 9 04) 16. Two batteries, one of emf 18 volts and internal resistance 22 and the other of emf 12 volt and internal resistance 12, are connected as shown. The voltmeter V will record a reading of 2. 1) 3 50 8. 2) v 9. 32 15 2 sa 4 3) V 4) 2V 3 23. The current in adjoining circuit will be 1) 15 volt 1) ampere 45 2) 30 volt 181202 2) ampere 30 n 4,30 a 3) 14 volt 4) 18 volt 15 1 ampere 10 12112 30 n 17. The n rows each containing m cells in series are joined in parallel. Maximum current is taken from this combination across an external resistance of 32 1 4) ampere 24. The reading of the ammeter as per figure shown resistance. If the total number of cells used are 24 and is internal resistance of each cell is 0.5 2 then 3 1) 2) A 4 1) m = 8, n = 3 2) m = 6,n = 4 2V 3) m = 12,n = 2 4) m = 2,n = 12 3) 4) 2 20 ww 18. The magnitude and direction of the circuit in the circuit shown will be ww 25. A battery of e.m.f 10V is connected to resistance as shown in figure. The potential difference VA-VB between the points A and B is 1) -2V 2) 2 V 3) 5 V 20 1) 7 A from a to b through e 3 7 A from b to a through e 10 "ww iHwb 20 2) 3 10 A 30 ww w 10 V 30 ww 3) 1 A from b to a through e 4) 1 A from a to b through e 4) V 10 V 11 1/81/2
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