12. Draw and label the structure for the following compounds, given the 1H-NMR data. a. C5H1002 Show your work for the computation of the integration. triplet (a) d 1.32 (17 mm)= singlet (b) d 2.17 (18 mm)= quartet(c) d 3.41 (12 mm)= singlet (d) d 4.33 (11 mm)= b. C9H12O doublet(a) multiplet(b) singlet (c) d 1.14 (36 mm)= d 2.52 (6 mm)= d 6.57 (7 mm)= doublet(d) d 7.19 (12 mm)= doublet(e) d 7.35 (14 mm)=
12. Draw and label the structure for the following compounds, given the 1H-NMR data. a. C5H1002 Show your work for the computation of the integration. triplet (a) d 1.32 (17 mm)= singlet (b) d 2.17 (18 mm)= quartet(c) d 3.41 (12 mm)= singlet (d) d 4.33 (11 mm)= b. C9H12O doublet(a) multiplet(b) singlet (c) d 1.14 (36 mm)= d 2.52 (6 mm)= d 6.57 (7 mm)= doublet(d) d 7.19 (12 mm)= doublet(e) d 7.35 (14 mm)=
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![12. Draw and label the structure for the following compounds, given the 1H-NMR data.
a. C5H1002
Show your work for the computation of the integration.
triplet (a)
d 1.32 (17 mm)=
singlet (b)
d 2.17 (18 mm)=
quartet(c)
d 3.41 (12 mm)=
singlet (d)
d 4.33 (11 mm)=
b. C9H12O
doublet(a)
multiplet(b)
singlet (c)
d 1.14 (36 mm)=
d 2.52 (6 mm)=
d 6.57 (7 mm)=
doublet(d)
d 7.19 (12 mm)=
doublet(e)
d 7.35 (14 mm)=](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8f17c6dd-733f-4e33-9f1a-f9bc93529afc%2F17634ca9-05cf-4948-b9d9-2e7f178e8388%2Fs111vyo_processed.jpeg&w=3840&q=75)
Transcribed Image Text:12. Draw and label the structure for the following compounds, given the 1H-NMR data.
a. C5H1002
Show your work for the computation of the integration.
triplet (a)
d 1.32 (17 mm)=
singlet (b)
d 2.17 (18 mm)=
quartet(c)
d 3.41 (12 mm)=
singlet (d)
d 4.33 (11 mm)=
b. C9H12O
doublet(a)
multiplet(b)
singlet (c)
d 1.14 (36 mm)=
d 2.52 (6 mm)=
d 6.57 (7 mm)=
doublet(d)
d 7.19 (12 mm)=
doublet(e)
d 7.35 (14 mm)=
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