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12. Carbon atoms 1, 2, and 3 in the following structure are classified, respectively, as: CH3 043 C, : C CH3 ༡༠ 21 CH3 CaŹ CH₂ C3: C+12 CH -2° CAZ 3° CHE CH3 1 CH2 13. 1) tertiary, primary, secondary 2) quaternary, primary, tertiary 3) quaternary, secondary, secondary (4) quaternary, secondary, tertiary The basic species are arranged in decreasing order of basicity in the sequence: A) F- > > > Step 1: Find conjugate acid OCH3NH2-CH3CH- Step 2: Determine pkaĴ B) OCH 3- > Ⓒ CHECK:3 CH2- D) NH2 E) NH2 > CH3CH2 > > F- > NH 2 > OCH 3 > F- CH3CH2 > F- OCH3 > CH3CH2 the weaker the base, the the conjugate acid OCH3- F- stronger 14-, Identify the conjugate bases in the following reactions. B. A C.B C.A d d CB HA + B = A + HBt -NH2 + HBr BA ☐ Θ Θ 4 4 - NH3 + Br 1 ။ B.A B.B C.B C2H5NH2 + H2CO3 = C₂H5NH3 + HCO3 B.A III. IV + (CH3)2NH + CH3CO₂H (CH3)2NH₂ + CH3CO2 BA V VI CB Θ CH3OH + H3PO4 - CH₂OH2 + H₂PO4 VII VIII a) I, III, V, VII b) II, IV, VI, VIII c) I, III, VI, VII d) II, IV, V, VIII آن 5

12. Carbon atoms 1, 2, and 3 in the following structure are classified, respectively, as: CH3 043 C, : C CH3 ༡༠ 21 CH3 CaŹ CH₂ C3: C+12 CH -2° CAZ 3° CHE CH3 1 CH2 13. 1) tertiary, primary, secondary 2) quaternary, primary, tertiary 3) quaternary, secondary, secondary (4) quaternary, secondary, tertiary The basic species are arranged in decreasing order of basicity in the sequence: A) F- > > > Step 1: Find conjugate acid OCH3NH2-CH3CH- Step 2: Determine pkaĴ B) OCH 3- > Ⓒ CHECK:3 CH2- D) NH2 E) NH2 > CH3CH2 > > F- > NH 2 > OCH 3 > F- CH3CH2 > F- OCH3 > CH3CH2 the weaker the base, the the conjugate acid OCH3- F- stronger 14-, Identify the conjugate bases in the following reactions. B. A C.B C.A d d CB HA + B = A + HBt -NH2 + HBr BA ☐ Θ Θ 4 4 - NH3 + Br 1 ။ B.A B.B C.B C2H5NH2 + H2CO3 = C₂H5NH3 + HCO3 B.A III. IV + (CH3)2NH + CH3CO₂H (CH3)2NH₂ + CH3CO2 BA V VI CB Θ CH3OH + H3PO4 - CH₂OH2 + H₂PO4 VII VIII a) I, III, V, VII b) II, IV, VI, VIII c) I, III, VI, VII d) II, IV, V, VIII آن 5

Introductory Chemistry For Today
Introductory Chemistry For Today
8th Edition
ISBN:9781285644561
Author:Seager
Publisher:Seager
Chapter9: Acids, Bases, And Salts
Section: Chapter Questions
Problem 9.15E
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(ME EX2) Problems 12-14 Could you please explain problems 12 through 14 to me in detail, step by step? Thank you so much! If necessary, please color-code them for me. 

12. Carbon atoms 1, 2, and 3 in the following structure are classified, respectively, as: CH3 043 C, : C CH3 ༡༠ 21 CH3 CaŹ CH₂ C3: C+12 CH -2° CAZ 3° CHE CH3 1 CH2 13. 1) tertiary, primary, secondary 2) quaternary, primary, tertiary 3) quaternary, secondary, secondary (4) quaternary, secondary, tertiary The basic species are arranged in decreasing order of basicity in the sequence: A) F- > > > Step 1: Find conjugate acid OCH3NH2-CH3CH- Step 2: Determine pkaĴ B) OCH 3- > Ⓒ CHECK:3 CH2- D) NH2 E) NH2 > CH3CH2 > > F- > NH 2 > OCH 3 > F- CH3CH2 > F- OCH3 > CH3CH2 the weaker the base, the the conjugate acid OCH3- F- stronger 14-, Identify the conjugate bases in the following reactions. B. A C.B C.A d d CB HA + B = A + HBt -NH2 + HBr BA ☐ Θ Θ 4 4 - NH3 + Br 1 ။ B.A B.B C.B C2H5NH2 + H2CO3 = C₂H5NH3 + HCO3 B.A III. IV + (CH3)2NH + CH3CO₂H (CH3)2NH₂ + CH3CO2 BA V VI CB Θ CH3OH + H3PO4 - CH₂OH2 + H₂PO4 VII VIII a) I, III, V, VII b) II, IV, VI, VIII c) I, III, VI, VII d) II, IV, V, VIII آن 5
Transcribed Image Text:12. Carbon atoms 1, 2, and 3 in the following structure are classified, respectively, as: CH3 043 C, : C CH3 ༡༠ 21 CH3 CaŹ CH₂ C3: C+12 CH -2° CAZ 3° CHE CH3 1 CH2 13. 1) tertiary, primary, secondary 2) quaternary, primary, tertiary 3) quaternary, secondary, secondary (4) quaternary, secondary, tertiary The basic species are arranged in decreasing order of basicity in the sequence: A) F- > > > Step 1: Find conjugate acid OCH3NH2-CH3CH- Step 2: Determine pkaĴ B) OCH 3- > Ⓒ CHECK:3 CH2- D) NH2 E) NH2 > CH3CH2 > > F- > NH 2 > OCH 3 > F- CH3CH2 > F- OCH3 > CH3CH2 the weaker the base, the the conjugate acid OCH3- F- stronger 14-, Identify the conjugate bases in the following reactions. B. A C.B C.A d d CB HA + B = A + HBt -NH2 + HBr BA ☐ Θ Θ 4 4 - NH3 + Br 1 ။ B.A B.B C.B C2H5NH2 + H2CO3 = C₂H5NH3 + HCO3 B.A III. IV + (CH3)2NH + CH3CO₂H (CH3)2NH₂ + CH3CO2 BA V VI CB Θ CH3OH + H3PO4 - CH₂OH2 + H₂PO4 VII VIII a) I, III, V, VII b) II, IV, VI, VIII c) I, III, VI, VII d) II, IV, V, VIII آن 5
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