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12. After examining 5000 records of children of age 5, a dentist finds that 2235 had at Teast one cavity on their first dental check-up. What empirical probability would the dentist assign to the event that a 5 vear old would have at least one cavity of his/her first dental check-up? 600 2225

12. After examining 5000 records of children of age 5, a dentist finds that 2235 had at Teast one cavity on their first dental check-up. What empirical probability would the dentist assign to the event that a 5 vear old would have at least one cavity of his/her first dental check-up? 600 2225

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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**Problem Statement:** After examining 5000 records of children of age 5, a dentist finds that 2235 had at least one cavity on their first dental check-up. What empirical probability would the dentist assign to the event that a 5-year-old would have at least one cavity at his/her first dental check-up? **Solution Explanation:** To calculate the empirical probability of a 5-year-old having at least one cavity at their first dental check-up, we use the formula for empirical probability: \[ \text{Empirical Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \] In this problem: - The number of favorable outcomes (children with at least one cavity) is 2235. - The total number of outcomes (total children examined) is 5000. The empirical probability is therefore: \[ \frac{2235}{5000} = 0.447 \] Thus, the empirical probability is 0.447, or 44.7%.
Transcribed Image Text:**Problem Statement:** After examining 5000 records of children of age 5, a dentist finds that 2235 had at least one cavity on their first dental check-up. What empirical probability would the dentist assign to the event that a 5-year-old would have at least one cavity at his/her first dental check-up? **Solution Explanation:** To calculate the empirical probability of a 5-year-old having at least one cavity at their first dental check-up, we use the formula for empirical probability: \[ \text{Empirical Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \] In this problem: - The number of favorable outcomes (children with at least one cavity) is 2235. - The total number of outcomes (total children examined) is 5000. The empirical probability is therefore: \[ \frac{2235}{5000} = 0.447 \] Thus, the empirical probability is 0.447, or 44.7%.
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