12. A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the time that the rocket will hit the ground, to the nearest 100oth of second. y = -16+ 247r+ 141
12. A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the time that the rocket will hit the ground, to the nearest 100oth of second. y = -16+ 247r+ 141
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter2: Equations And Inequalities
Section: Chapter Questions
Problem 3T
Related questions
Question
![12.
A rocket is launched from a tower. The height of
the rocket, y in feet, is related to the time after
launch, x in seconds, by the given equation.
Using this equation, find the time that the
rocket will hit the ground, to the nearest 10oth
of second.
y = -16x + 247x + 141](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F71125a40-5a95-4ab3-b2aa-53217c0007a2%2F720575d6-1c50-41e0-b992-464793198557%2Fmil416n_processed.jpeg&w=3840&q=75)
Transcribed Image Text:12.
A rocket is launched from a tower. The height of
the rocket, y in feet, is related to the time after
launch, x in seconds, by the given equation.
Using this equation, find the time that the
rocket will hit the ground, to the nearest 10oth
of second.
y = -16x + 247x + 141
![11.
A rocket is launched from a tower. The height of
the rocket, y in feet, is related to the time after
launch, x in seconds, by the given equation.
Using this equation, find out the time at which
the rocket will reach its max, to the nearest
100th of a second.
y = -16z + 263x + 92](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F71125a40-5a95-4ab3-b2aa-53217c0007a2%2F720575d6-1c50-41e0-b992-464793198557%2Fbwoenqf_processed.jpeg&w=3840&q=75)
Transcribed Image Text:11.
A rocket is launched from a tower. The height of
the rocket, y in feet, is related to the time after
launch, x in seconds, by the given equation.
Using this equation, find out the time at which
the rocket will reach its max, to the nearest
100th of a second.
y = -16z + 263x + 92
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