12. (2y? + 3xy – 2y+ 6x)dx + x(x+2y – 1)dy = 0 %3D

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Choose two from the list below and solve for its differential equation.

12. (2y? + 3ху — 2у + 6х)dx + х(х+ 2у— 1)dy%3D0
13.ydx + (3x –xy + 2)dy = 0
14. (x3 + ху? + у)dx + (уз + x?у + x)dy — 0
15. (x² + y²)dx – xydy = 0
16.e" yy'
17. y' = x – 2y cot 2x
18. (3x?y – 3y)dx + (x³ + 8y – 3x)dy = 0
19. (x – y)dx + (3x + y)dy = 0
20. ydx + 2(y* — х)dy %3D 0
21. 2(2y² + 5xy – 2y + 4)dx + x(2x + 2y – 1)dy = 0
22.(3x² – 2y²)y' = 2xy ;
= x COS X
%3D
x = 1, y=1
Transcribed Image Text:12. (2y? + 3ху — 2у + 6х)dx + х(х+ 2у— 1)dy%3D0 13.ydx + (3x –xy + 2)dy = 0 14. (x3 + ху? + у)dx + (уз + x?у + x)dy — 0 15. (x² + y²)dx – xydy = 0 16.e" yy' 17. y' = x – 2y cot 2x 18. (3x?y – 3y)dx + (x³ + 8y – 3x)dy = 0 19. (x – y)dx + (3x + y)dy = 0 20. ydx + 2(y* — х)dy %3D 0 21. 2(2y² + 5xy – 2y + 4)dx + x(2x + 2y – 1)dy = 0 22.(3x² – 2y²)y' = 2xy ; = x COS X %3D x = 1, y=1
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