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12) The solution of 2lnx-In(x+ 2)=In2 is a) 0 b) 1 c) {-1,4) d) 4 e) поп 13) sin( 2 csc"1(2)) = b) - a) d) 4 e) non 13x-1= 14) limx-1 1-3x a) -1 b) 1 c) -2 d) DNE e) non 15) limx--2 xt-16 x2+3x+2 %3D d) DNE e)non a) 32 c) 3 b) 1 Vx2+5 %3D 16) limy→-∞ 1–5x d) DNE e) non b) a) 116 115

12) The solution of 2lnx-In(x+ 2)=In2 is a) 0 b) 1 c) {-1,4) d) 4 e) поп 13) sin( 2 csc"1(2)) = b) - a) d) 4 e) non 13x-1= 14) limx-1 1-3x a) -1 b) 1 c) -2 d) DNE e) non 15) limx--2 xt-16 x2+3x+2 %3D d) DNE e)non a) 32 c) 3 b) 1 Vx2+5 %3D 16) limy→-∞ 1–5x d) DNE e) non b) a) 116 115

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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12) The solution of 2lnx-In(x+ 2)= In2 is a) 0 b) 1 c) {-1,4) d) 4 e) пon 13) sin(2 csc"1(2)) = a) b)- d) 4 e) non 13x-1= 14) limy-1 1-3x a) -1 b) 1 c) -2 d) DNE e) non x2+3x+2 15) limx-2 xt-16 %3D a) 32 c) 3 d) DNE e)non b) 1 Vx2+5 16) limy→-∞ 1–5x %3D d) DNE e) non b) a) 116 115
Transcribed Image Text:12) The solution of 2lnx-In(x+ 2)= In2 is a) 0 b) 1 c) {-1,4) d) 4 e) пon 13) sin(2 csc"1(2)) = a) b)- d) 4 e) non 13x-1= 14) limy-1 1-3x a) -1 b) 1 c) -2 d) DNE e) non x2+3x+2 15) limx-2 xt-16 %3D a) 32 c) 3 d) DNE e)non b) 1 Vx2+5 16) limy→-∞ 1–5x %3D d) DNE e) non b) a) 116 115
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