(12 On the interval [4, 12], the graph is a semi-circle. Since the semi-circle is below the x-axis, then 9(x) dx is the negative of the area of this semi-circle. The radius of this semi-circle is r= 4 (Give the numeric value.) Step 2 A circle of radius r has an area A = 2 and so our semi-circle has an area A = 8T

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