12 m 12 m A 3 m В 3 m Figure 1 Figure 2 A simple trebuchet is constructed as shown above.The projectile mass, ma = M = 1.50 kg, and the counterweight mass, mg = cM, where c is 7.50 x 102. Relative to the masses of the projectile and counterweight, the mass of the rotating arm is assumed negligible and there is no friction in the pivot.There is a mechanism that stops the arm when it becomes vertical, allowing the projectile to be launched horizontally. {If needed, treat both masses as point masses with moment of inertia = (mass)R2.} a. Determine the tangential speed of the projectile at the top of the motion as it leaves the trebuchet. Blank 1 b. How long is the projectile is in the air? Blank 2 Do Not Enter Units In Answers. Show All Starting Equations And Ideas That Lead To Your Answers. Blank 1 Add your answer Blank 2 Add your answer

University Physics Volume 1
18th Edition
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Chapter10: Fixed-axis Rotation
Section: Chapter Questions
Problem 90P: A uniform cylindrical grinding wheel of mass 50.0 kg and diameter 1.0 m is turned on by an electric...
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12 m
12 m
A
3 m
B
3 m
Figure 1
Figure 2
A simple trebuchet is constructed as shown above.The projectile mass, ma = M = 1.50 kg, and the
counterweight mass, mg = cM, where c is 7.50 x 102. Relative to the masses of the projectile and
counterweight, the mass of the rotating arm is assumed negligible and there is no friction in the
pivot.There is a mechanism that stops the arm when it becomes vertical, allowing the projectile to be
launched horizontally. {If needed, treat both masses as point masses with moment of inertia = (mass)R2.}
a. Determine the tangential speed of the projectile at the top of the motion as it leaves the
trebuchet.
Blank 1
b. How long is the projectile is in the air?
Blank 2
Do Not Enter Units In Answers. Show All Starting Equations And Ideas That Lead To Your Answers.
Blank 1
Add your answer
Blank 2
Add your answer
Transcribed Image Text:12 m 12 m A 3 m B 3 m Figure 1 Figure 2 A simple trebuchet is constructed as shown above.The projectile mass, ma = M = 1.50 kg, and the counterweight mass, mg = cM, where c is 7.50 x 102. Relative to the masses of the projectile and counterweight, the mass of the rotating arm is assumed negligible and there is no friction in the pivot.There is a mechanism that stops the arm when it becomes vertical, allowing the projectile to be launched horizontally. {If needed, treat both masses as point masses with moment of inertia = (mass)R2.} a. Determine the tangential speed of the projectile at the top of the motion as it leaves the trebuchet. Blank 1 b. How long is the projectile is in the air? Blank 2 Do Not Enter Units In Answers. Show All Starting Equations And Ideas That Lead To Your Answers. Blank 1 Add your answer Blank 2 Add your answer
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