12 In order to save an endangered species, it has been decided to release 40 animals on an island where there are no predators. The maximum number that can survive on the island is called the carrying capacity, which is 1000. It is assumed that the population N of these animals at time t years after release fits the logistic growth equation dN = kN (1000 dt - N), for some constant k. 1000 1 1 a Show that N(1000 – N) N 1000 – N b Use the result of part a to find the general solution of the logistic growth equation. c Determine the arbitrary constant by applying the initial condition N(0) = 40, then simplify the function. d Given that the population of animals after 1 year was 80, find the value of k correct to four significant figures. e What will the population be after 5 years, correct to the nearest whole number?

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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12 In order to save an endangered species, it has been decided to release 40 animals on an island where
there are no predators. The maximum number that can survive on the island is called the carrying
capacity, which is 1000. It is assumed that the population N of these animals at time t years after release
fits the logistic growth equation
dN
= kN (1000
dt
N),
for some constant k.
1000
1
+
1000 – N
1
a Show that
N(1000 – N)
b Use the result of part a to find the general solution of the logistic growth equation.
c Determine the arbitrary constant by applying the initial condition N (0)
40, then simplify the
function.
d Given that the population of animals after 1 year was 80, find the value of k correct to four significant
figures.
e What will the population be after 5 years, correct to the nearest whole number?
Transcribed Image Text:12 In order to save an endangered species, it has been decided to release 40 animals on an island where there are no predators. The maximum number that can survive on the island is called the carrying capacity, which is 1000. It is assumed that the population N of these animals at time t years after release fits the logistic growth equation dN = kN (1000 dt N), for some constant k. 1000 1 + 1000 – N 1 a Show that N(1000 – N) b Use the result of part a to find the general solution of the logistic growth equation. c Determine the arbitrary constant by applying the initial condition N (0) 40, then simplify the function. d Given that the population of animals after 1 year was 80, find the value of k correct to four significant figures. e What will the population be after 5 years, correct to the nearest whole number?
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