12 In a survey of 1466 ​people, 1103 people said they voted in a recent presidential election. Voting records show that 73​% of eligible voters actually did vote. Given that 73​% of eligible voters actually did​ vote, (a) find the probability that among 1466 randomly selected​ voters, at least 1103 actually did vote.​ (b) What do the results from part​ (a) suggest?       ​(a) ​P(X≥1103​)=nothing ​(Round to four decimal places as​ needed.) ​(b) What does the result from part​ (a) suggest?     A. People are being honest because the probability of ​P(x≥1103​) is at least​ 1%.   B. Some people are being less than honest because ​P(x≥1103​) is at least​ 1%.   C. People are being honest because the probability of ​P(x≥1103​) is less than​ 5%.   D. Some people are being less than honest because ​P(x≥1103​) is less than​ 5%.

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section11.8: Probabilities Of Disjoint And Overlapping Events
Problem 2C
Question

12

In a survey of
1466
​people,
1103
people said they voted in a recent presidential election. Voting records show that
73​%
of eligible voters actually did vote. Given that
73​%
of eligible voters actually did​ vote, (a) find the probability that among
1466
randomly selected​ voters, at least
1103
actually did vote.​ (b) What do the results from part​ (a) suggest?
 
 
 
​(a)
​P(X≥1103​)=nothing
​(Round to four decimal places as​ needed.)
​(b) What does the result from part​ (a) suggest?
 
 
A.
People are being honest because the probability of
​P(x≥1103​)
is at least​ 1%.
 
B.
Some people are being less than honest because
​P(x≥1103​)
is at least​ 1%.
 
C.
People are being honest because the probability of
​P(x≥1103​)
is less than​ 5%.
 
D.
Some people are being less than honest because
​P(x≥1103​)
is less than​ 5%.
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