12-G. Iminodiacetic acid forms 2:1 complexes with many metal ions: CH2CO;H H2N = H3X* CH2CO3H ax2 = [H,X]+[H,X]+[HX]+[X²] Cu?+ + 2X?- = CuX; K = B2 = 3.5 × 1016 %3D A 25.0-mL solution containing 0.120 M iminodiacetic acid buffered to pH 7.00 was titrated with 25.0 mL of 0.050 0 M Cu+. Given that ax2 = 4.6 x 10 3 at pH 7.00, calculate [Cu+] in the resulting solution.
12-G. Iminodiacetic acid forms 2:1 complexes with many metal ions: CH2CO;H H2N = H3X* CH2CO3H ax2 = [H,X]+[H,X]+[HX]+[X²] Cu?+ + 2X?- = CuX; K = B2 = 3.5 × 1016 %3D A 25.0-mL solution containing 0.120 M iminodiacetic acid buffered to pH 7.00 was titrated with 25.0 mL of 0.050 0 M Cu+. Given that ax2 = 4.6 x 10 3 at pH 7.00, calculate [Cu+] in the resulting solution.
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Chapter1: Chemical Foundations
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![12-G. Iminodiacetic acid forms 2:1 complexes with many metal ions:
+-CH2CO;H
H2N
=H3X*
CH2CO3H
ax2
|3D
[H,X*]+[H,X]+[HX]+[X*]
Cu²+ + 2X2- = CuX
K = B, = 3.5 x 1016
%3D
A 25.0-mL solution containing 0.120 M iminodiacetic acid buffered to pH 7.00 was
= 4.6 x 10 3 at pH 7.00,
titrated with 25.0 mL of 0.050 0 M Cut.Given that ay2
calculate (Cu+] in the resulting solution.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F153e58aa-cf8f-4432-80f5-f7396a860227%2F045caab5-1770-4e91-8e2a-a5cef770a3a5%2Fvaj4we_processed.jpeg&w=3840&q=75)
Transcribed Image Text:12-G. Iminodiacetic acid forms 2:1 complexes with many metal ions:
+-CH2CO;H
H2N
=H3X*
CH2CO3H
ax2
|3D
[H,X*]+[H,X]+[HX]+[X*]
Cu²+ + 2X2- = CuX
K = B, = 3.5 x 1016
%3D
A 25.0-mL solution containing 0.120 M iminodiacetic acid buffered to pH 7.00 was
= 4.6 x 10 3 at pH 7.00,
titrated with 25.0 mL of 0.050 0 M Cut.Given that ay2
calculate (Cu+] in the resulting solution.
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