the y is 57 12) From the following heats of combustion,CH,OH(I) + 0,(g)CO:(g) + 2H,0(1)AHn = -726.4 kJ/molC(graphite) + O,(8) CO,(g)AHn = -393.5 kJ/molH,O(1)AHan = -285.8 kJ/molH2(8) + 0,(g)-calculate the enthalpy of formation of methanol (CH3OH) from its elements:C(graphite) + 2H2(g) + }0,(8) CH,OH(I)13) How many mL of a 0.375 M solution can be made from Y g of Ca3(PO4)2 (molarmass=310 g/mole)?14) A solution concentration is Y ppm and is made with a solute that has molar mass equal to650 g/mol. What is the molarity of the solution?

12) Given chemical reaction is, C(graphite) + 2H2(g) + 1/2O2 ---> CH3OH(l) The given reactions…

12) From the following heats of combustion, CH,OH(1) + 0,(8) CO.(g) + 2H,0(1) AHn = -726.4 kJ/mol → CO(g) AHan = -393.5 kJ/mol H,O(I) AHn = -285.8 kJ/mol C(graphite) + O,(g) H,(8) + 0,(8) calculate the enthalpy of formation of methanol (CH3OH) from its elements: C(graphite) + 2H2(g) + 0,() CH,OH(I) 13) How many mL of a 0.375 M solution can be made from Y g of Ca3(PO4)2 (molar mass=310 g/mole)? 14) A solution concentration is Y ppm and is made with a solute that has molar mass equal to 650 g/mol. What is the molarity of the solution?

12) From the following heats of combustion, CH,OH(1) + 0,(8) CO.(g) + 2H,0(1) AHn = -726.4 kJ/mol → CO(g) AHan = -393.5 kJ/mol H,O(I) AHn = -285.8 kJ/mol C(graphite) + O,(g) H,(8) + 0,(8) calculate the enthalpy of formation of methanol (CH3OH) from its elements: C(graphite) + 2H2(g) + 0,() CH,OH(I) 13) How many mL of a 0.375 M solution can be made from Y g of Ca3(PO4)2 (molar mass=310 g/mole)? 14) A solution concentration is Y ppm and is made with a solute that has molar mass equal to 650 g/mol. What is the molarity of the solution?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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