12) Determine the shear capacity, øVc, for a one foot- wide design strip for a solid 8 in. deep of normal weight concrete. fc=3 ksi, fy = 40 ksi, d= 6.94 in. one-way slab
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- 1. A simply supported beam has a clear span of= 22 ft. and is subjected to a factored uniform load of 3.3 k/ft. The distance from the extreme compression fiber to centroid of longitudinal tension reinforcing steel is 17 inches. Assume f.' = 4,000 psi, and fy = 60,000 psi. The factored shear force at the critical section is most nearly: a) 36.3 kips b) 33 kips c) 28.8 kips d) 31.6 kips7.15 A new sports stadium is being proposed for a city in North Dakota. Some of the project details are as follows. To prepare for the footing and foundation 300 000 cubic yards of dirt will need to be removed. It will have an inflatable roof that covers 10.0 acres and its interior volume will be 60.0 × 106 cubic feet. During construction, 40.0 × 103 cubic yards of concrete, 11.9 × 103 tons of reinforcing steel and 5.00 × 102 tons of structural steel will be utilized. The roof material will include an outer layer of Teflon-coated fiberglass together with an inner layer of woven fiberglass. Given this information, answer the following: (a) If removed evenly over the 10 acres, how deep of a hole would be formed as a result of the excavation? (b) What is the total mass of concrete and steel in lbm? (c) If the two-layer fiberglass roofing material has a mass of 0.6667 lbm/ft², what is the total mass of the roof? (d) If 10.0 in, of wet snow is collected on the roof, what is the added mass…2. Casson model was discussed in class in the context of blood rheology. This phenomenological model is often used to describe the shear stress vs. shear rate relationship in colloidal suspensions where particle aggregation might cause the measured viscosity to increase at low shear rates. In an experiment, data for the shear stress rand the applied shear rate S were fitted to the Casson model written below (in a slightly different form compared to that given in the lecture notes): √t=√₁+√as. (1) The best least square fit parameters to the experimental data were found to be 40 mPa for the yield stress and 2.5 mPas for the parameter a, which is referred to as the plastic viscosity. a. Using Eq. (1), derive an expression for the fluid viscosity u as a function of S. b. Plot the viscosity of the fluid as a function of S for 0.1s¹