12) A 5 kg ball moving to the right at a speed of 6 m/s strikes another 4 kg ball moving to the left at 5 m/s. What is the velocity of each ball after the elastic collision?

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**Problem 12**

A 5 kg ball moving to the right at a speed of 6 m/s strikes another 4 kg ball moving to the left at 5 m/s. What is the velocity of each ball after the elastic collision?

*Solution:*

To solve this problem, we can use the conservation of momentum and the conservation of kinetic energy, which apply to elastic collisions.

1. **Conservation of Momentum:**

   \[
   m_1 \cdot v_{1i} + m_2 \cdot v_{2i} = m_1 \cdot v_{1f} + m_2 \cdot v_{2f}
   \]

   Where:
   - \( m_1 = 5 \, \text{kg} \)
   - \( v_{1i} = 6 \, \text{m/s} \)
   - \( m_2 = 4 \, \text{kg} \)
   - \( v_{2i} = -5 \, \text{m/s} \) (negative because it's moving to the left)
   - \( v_{1f} \) and \( v_{2f} \) are the final velocities of balls 1 and 2, respectively.

2. **Conservation of Kinetic Energy:**

   \[
   \frac{1}{2} m_1 v_{1i}^2 + \frac{1}{2} m_2 v_{2i}^2 = \frac{1}{2} m_1 v_{1f}^2 + \frac{1}{2} m_2 v_{2f}^2
   \]

By solving the system of equations derived from these two principles, you can find the final velocities \( v_{1f} \) and \( v_{2f} \).
Transcribed Image Text:**Problem 12** A 5 kg ball moving to the right at a speed of 6 m/s strikes another 4 kg ball moving to the left at 5 m/s. What is the velocity of each ball after the elastic collision? *Solution:* To solve this problem, we can use the conservation of momentum and the conservation of kinetic energy, which apply to elastic collisions. 1. **Conservation of Momentum:** \[ m_1 \cdot v_{1i} + m_2 \cdot v_{2i} = m_1 \cdot v_{1f} + m_2 \cdot v_{2f} \] Where: - \( m_1 = 5 \, \text{kg} \) - \( v_{1i} = 6 \, \text{m/s} \) - \( m_2 = 4 \, \text{kg} \) - \( v_{2i} = -5 \, \text{m/s} \) (negative because it's moving to the left) - \( v_{1f} \) and \( v_{2f} \) are the final velocities of balls 1 and 2, respectively. 2. **Conservation of Kinetic Energy:** \[ \frac{1}{2} m_1 v_{1i}^2 + \frac{1}{2} m_2 v_{2i}^2 = \frac{1}{2} m_1 v_{1f}^2 + \frac{1}{2} m_2 v_{2f}^2 \] By solving the system of equations derived from these two principles, you can find the final velocities \( v_{1f} \) and \( v_{2f} \).
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