12) A 5 kg ball moving to the right at a speed of 6 m/s strikes another 4 kg ball moving to the left at 5 m/s. What is the velocity of each ball after the elastic collision?
12) A 5 kg ball moving to the right at a speed of 6 m/s strikes another 4 kg ball moving to the left at 5 m/s. What is the velocity of each ball after the elastic collision?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Problem 12**
A 5 kg ball moving to the right at a speed of 6 m/s strikes another 4 kg ball moving to the left at 5 m/s. What is the velocity of each ball after the elastic collision?
*Solution:*
To solve this problem, we can use the conservation of momentum and the conservation of kinetic energy, which apply to elastic collisions.
1. **Conservation of Momentum:**
\[
m_1 \cdot v_{1i} + m_2 \cdot v_{2i} = m_1 \cdot v_{1f} + m_2 \cdot v_{2f}
\]
Where:
- \( m_1 = 5 \, \text{kg} \)
- \( v_{1i} = 6 \, \text{m/s} \)
- \( m_2 = 4 \, \text{kg} \)
- \( v_{2i} = -5 \, \text{m/s} \) (negative because it's moving to the left)
- \( v_{1f} \) and \( v_{2f} \) are the final velocities of balls 1 and 2, respectively.
2. **Conservation of Kinetic Energy:**
\[
\frac{1}{2} m_1 v_{1i}^2 + \frac{1}{2} m_2 v_{2i}^2 = \frac{1}{2} m_1 v_{1f}^2 + \frac{1}{2} m_2 v_{2f}^2
\]
By solving the system of equations derived from these two principles, you can find the final velocities \( v_{1f} \) and \( v_{2f} \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2f619dbb-fdef-460b-b92d-9112a1596c50%2F00837f23-9970-4c2a-a509-5f8f6945f800%2Foitnvz_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem 12**
A 5 kg ball moving to the right at a speed of 6 m/s strikes another 4 kg ball moving to the left at 5 m/s. What is the velocity of each ball after the elastic collision?
*Solution:*
To solve this problem, we can use the conservation of momentum and the conservation of kinetic energy, which apply to elastic collisions.
1. **Conservation of Momentum:**
\[
m_1 \cdot v_{1i} + m_2 \cdot v_{2i} = m_1 \cdot v_{1f} + m_2 \cdot v_{2f}
\]
Where:
- \( m_1 = 5 \, \text{kg} \)
- \( v_{1i} = 6 \, \text{m/s} \)
- \( m_2 = 4 \, \text{kg} \)
- \( v_{2i} = -5 \, \text{m/s} \) (negative because it's moving to the left)
- \( v_{1f} \) and \( v_{2f} \) are the final velocities of balls 1 and 2, respectively.
2. **Conservation of Kinetic Energy:**
\[
\frac{1}{2} m_1 v_{1i}^2 + \frac{1}{2} m_2 v_{2i}^2 = \frac{1}{2} m_1 v_{1f}^2 + \frac{1}{2} m_2 v_{2f}^2
\]
By solving the system of equations derived from these two principles, you can find the final velocities \( v_{1f} \) and \( v_{2f} \).
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