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12 2.0 m 3,0 m

12 2.0 m 3,0 m

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Superposition Principle

1. Using the same charge configuration in Example 1.1, find the

resultant electric force on ?2.

EXAMPLE 1.1 Force of Three Charges in a Line > Three point charges are located along the x-axis. Point charge q, = +3.5 × 10-6 C is at x = 0, point charge q2 = +8.5 × 10-6 C is at 93 = -5.0 × 10-6 C is at x = 3.0 m. Find the resultant electric force acting on q1. x = 2.0 m, and point charge 92 Is 2.0 m 3,0 m Given: Find: q1 = +3.5 × 10-6 C 92 = +8.5 × 10-6 C 93 = -5.0 × 10-6 C 12 on 1 = 2.0 m 13 on 1 = 3.0 m F2 on 1 = ? F3 on 1 = ? Fresultant = ? Solution: a. First, let's find the force exerted by 92 on q1. |q192| : = (9 × 10° N · m²/C²) |(+3.5 × 10-6 C)(+8.5 × 10-6 C)| F2 on 1 = k (r2 on 1)² (2.0 m)² |+2.98 × 10-11 C| F2 on 1 = (9 × 10º N · m² /C²) 4.0 m² F2 on 1 = (9 × 10° N · m² /C²)(+7.45 × 10-12 C /m²) = 0.07 N Point charge q2 repels q1. Thus, F2 on 1 is directed to the left. b. For the force exerted by q3 on q1, (9 × 10° N · m²/C²). |(+3.5 × 10-6 C)(-5.0 × 10-6 C)| (3.0 m)² F3 on 1 = k ´ (r2 on 1)² |-1.75 × 10-11 C| F3 on 1 = (9 × 10° N · m² /C²) F3 on 1 = (9 × 10° N · m² /C²)(1.94 × 10-12 C/m²) = 0.02 N 9.0 m² Point charge q3 attracts q1. Therefore, F3 on 1 is directed to the right. Setting the left direction to be negative and the right direction to be positive, the magnitude F of the resultant force is directed to the left. Fresultant = F2 on 1 + F3 on 1 = -0.07 N + 0.02 N = –0.05 N, 12 Fresultaut Fy on 1 F2 on 1 0 2.0 m 3.0 ш 1
Transcribed Image Text:EXAMPLE 1.1 Force of Three Charges in a Line > Three point charges are located along the x-axis. Point charge q, = +3.5 × 10-6 C is at x = 0, point charge q2 = +8.5 × 10-6 C is at 93 = -5.0 × 10-6 C is at x = 3.0 m. Find the resultant electric force acting on q1. x = 2.0 m, and point charge 92 Is 2.0 m 3,0 m Given: Find: q1 = +3.5 × 10-6 C 92 = +8.5 × 10-6 C 93 = -5.0 × 10-6 C 12 on 1 = 2.0 m 13 on 1 = 3.0 m F2 on 1 = ? F3 on 1 = ? Fresultant = ? Solution: a. First, let's find the force exerted by 92 on q1. |q192| : = (9 × 10° N · m²/C²) |(+3.5 × 10-6 C)(+8.5 × 10-6 C)| F2 on 1 = k (r2 on 1)² (2.0 m)² |+2.98 × 10-11 C| F2 on 1 = (9 × 10º N · m² /C²) 4.0 m² F2 on 1 = (9 × 10° N · m² /C²)(+7.45 × 10-12 C /m²) = 0.07 N Point charge q2 repels q1. Thus, F2 on 1 is directed to the left. b. For the force exerted by q3 on q1, (9 × 10° N · m²/C²). |(+3.5 × 10-6 C)(-5.0 × 10-6 C)| (3.0 m)² F3 on 1 = k ´ (r2 on 1)² |-1.75 × 10-11 C| F3 on 1 = (9 × 10° N · m² /C²) F3 on 1 = (9 × 10° N · m² /C²)(1.94 × 10-12 C/m²) = 0.02 N 9.0 m² Point charge q3 attracts q1. Therefore, F3 on 1 is directed to the right. Setting the left direction to be negative and the right direction to be positive, the magnitude F of the resultant force is directed to the left. Fresultant = F2 on 1 + F3 on 1 = -0.07 N + 0.02 N = –0.05 N, 12 Fresultaut Fy on 1 F2 on 1 0 2.0 m 3.0 ш 1
Work It Up Directions: Solve the following problems. Write your answers in a sheet of paper. Superposition Principle 1. Using the same charge configuration in Example 1.1, find the resultant electric force on q2. 2. Suppose that the charges in Example 1.3 are situated as shown in the figure. Find the resultant electric force on the charge at I. А. 3. What is the magnitude and direction of the electric field at 0.25 m from a -5.6 × 10-6C point charge? 4. Four point charges are equally separated by 1.00 m in air as shown. If q, = 3.0 nC, q2 = –4.0 nC, q3 = 2.0 nC, and q4 = –5.0 nC, what is the electric field at a point halfway between q2 and q3? 1.00 m 1.00 m 1.00 m
Transcribed Image Text:Work It Up Directions: Solve the following problems. Write your answers in a sheet of paper. Superposition Principle 1. Using the same charge configuration in Example 1.1, find the resultant electric force on q2. 2. Suppose that the charges in Example 1.3 are situated as shown in the figure. Find the resultant electric force on the charge at I. А. 3. What is the magnitude and direction of the electric field at 0.25 m from a -5.6 × 10-6C point charge? 4. Four point charges are equally separated by 1.00 m in air as shown. If q, = 3.0 nC, q2 = –4.0 nC, q3 = 2.0 nC, and q4 = –5.0 nC, what is the electric field at a point halfway between q2 and q3? 1.00 m 1.00 m 1.00 m
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