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117 +i sin 12 117 = cos-+i sin- where 0se< 2x. 6 and Find the quotient of z = 4| cos 12 z2 6 21 = 3cis 4 22 137 21 = 4 cis- 12 2 1 Z1 -=- C1S- 22 4 4 Z1 = 4 cis- 4 22

117 +i sin 12 117 = cos-+i sin- where 0se< 2x. 6 and Find the quotient of z = 4| cos 12 z2 6 21 = 3cis 4 22 137 21 = 4 cis- 12 2 1 Z1 -=- C1S- 22 4 4 Z1 = 4 cis- 4 22

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
117 Find the quotient of z = 4 cos +i sin 12 4. 117 and z, = cos+i sin where 0se < 2x. 12 21 = 3cis 4 22 137 21 = 4 cis 22 12 1 21 =- C1 S Z2 4 4 21 = 4 cis- 22 4
Transcribed Image Text:117 Find the quotient of z = 4 cos +i sin 12 4. 117 and z, = cos+i sin where 0se < 2x. 12 21 = 3cis 4 22 137 21 = 4 cis 22 12 1 21 =- C1 S Z2 4 4 21 = 4 cis- 22 4
1. Given z, = 5| cos- 377 -+i sin 2 37 and z2 = 37 ,find zz, where 0se< 2x. Cos +i sin 2 10/cos 37 -+i sin 2 O z2 = 2.5(cosn+isin 7) O zz2 = 10(cos T +i sin 7) 122 = 10(cos 37+i sin 37) 2. Find the product of z = 9 cis 10° and z2 = 5 cis 3° where 0se<360°. 2122 = 14 cis 13° 2122 = 45 cis 13° 2122 = 45cis 7° 222 = 1.8cis 7° 3. Given z = 6(cos 45° +i sin 45°) and z2 = 2(cos 90° +i sin 90°), find Z1 where 0se<360°. 22 O 21 = 3(cos 45°+i sin 45°) 22 O 21 = 3(cos 315°+i sin 315°) 22 21 = 4 (cos 315°+i sin 315°) 22 %3D 21 - = 12(cos135°+i sin 135°)
Transcribed Image Text:1. Given z, = 5| cos- 377 -+i sin 2 37 and z2 = 37 ,find zz, where 0se< 2x. Cos +i sin 2 10/cos 37 -+i sin 2 O z2 = 2.5(cosn+isin 7) O zz2 = 10(cos T +i sin 7) 122 = 10(cos 37+i sin 37) 2. Find the product of z = 9 cis 10° and z2 = 5 cis 3° where 0se<360°. 2122 = 14 cis 13° 2122 = 45 cis 13° 2122 = 45cis 7° 222 = 1.8cis 7° 3. Given z = 6(cos 45° +i sin 45°) and z2 = 2(cos 90° +i sin 90°), find Z1 where 0se<360°. 22 O 21 = 3(cos 45°+i sin 45°) 22 O 21 = 3(cos 315°+i sin 315°) 22 21 = 4 (cos 315°+i sin 315°) 22 %3D 21 - = 12(cos135°+i sin 135°)
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