1165:0100 B84518 1165:0103 BB3478 1165:0106 01C3 1165:0108 48 1165:0109 4B 1165:010A 891E0001 1165:010E CD20 MOV AX, 1845 BX,7834 BX, AX MOV ADD DEC AX DEC BX MOV [01001, BX INT 20 You have used DEBUG to unassemble the above code. The entire program is bytes long. 8 16 64 010E 1165
1165:0100 B84518 1165:0103 BB3478 1165:0106 01C3 1165:0108 48 1165:0109 4B 1165:010A 891E0001 1165:010E CD20 MOV AX, 1845 BX,7834 BX, AX MOV ADD DEC AX DEC BX MOV [01001, BX INT 20 You have used DEBUG to unassemble the above code. The entire program is bytes long. 8 16 64 010E 1165
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
![## Analyzing Assembly Code
The image shows the following assembly instructions after using DEBUG to disassemble the code:
```
1165:0100 B84518 MOV AX,1845
1165:0103 BB3478 MOV BX,7834
1165:0106 01C3 ADD BX,AX
1165:0108 48 DEC AX
1165:0109 4B DEC BX
1165:010A 891E0100 MOV [0100],BX
1165:010E CD20 INT 20
```
### Question
You have used DEBUG to unassemble the above code.
The entire program is ________ bytes long.
### Multiple Choice Options
- ○ 8
- ○ 16
- ○ 64
- ○ 010E
- ○ 1165
### Explanation
To calculate the number of bytes:
- Each line of code contains opcodes and operands.
- Count the bytes for each instruction, as shown by the hex codes in the disassembly.
**Detailed Byte Breakdown:**
1. `MOV AX,1845` (B84518): 3 bytes
2. `MOV BX,7834` (BB3478): 3 bytes
3. `ADD BX,AX` (01C3): 2 bytes
4. `DEC AX` (48): 1 byte
5. `DEC BX` (4B): 1 byte
6. `MOV [0100],BX` (891E0100): 4 bytes
7. `INT 20` (CD20): 2 bytes
**Total Length**
- Sum the bytes: 3 + 3 + 2 + 1 + 1 + 4 + 2 = 16 bytes
Correct Answer: **16**](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdd3494d7-16cb-4f96-a1a3-f69334a1e65b%2Ffbbd3f79-68c6-4dd0-a928-2971c4cfab59%2Fnd4uogm_processed.png&w=3840&q=75)
Transcribed Image Text:## Analyzing Assembly Code
The image shows the following assembly instructions after using DEBUG to disassemble the code:
```
1165:0100 B84518 MOV AX,1845
1165:0103 BB3478 MOV BX,7834
1165:0106 01C3 ADD BX,AX
1165:0108 48 DEC AX
1165:0109 4B DEC BX
1165:010A 891E0100 MOV [0100],BX
1165:010E CD20 INT 20
```
### Question
You have used DEBUG to unassemble the above code.
The entire program is ________ bytes long.
### Multiple Choice Options
- ○ 8
- ○ 16
- ○ 64
- ○ 010E
- ○ 1165
### Explanation
To calculate the number of bytes:
- Each line of code contains opcodes and operands.
- Count the bytes for each instruction, as shown by the hex codes in the disassembly.
**Detailed Byte Breakdown:**
1. `MOV AX,1845` (B84518): 3 bytes
2. `MOV BX,7834` (BB3478): 3 bytes
3. `ADD BX,AX` (01C3): 2 bytes
4. `DEC AX` (48): 1 byte
5. `DEC BX` (4B): 1 byte
6. `MOV [0100],BX` (891E0100): 4 bytes
7. `INT 20` (CD20): 2 bytes
**Total Length**
- Sum the bytes: 3 + 3 + 2 + 1 + 1 + 4 + 2 = 16 bytes
Correct Answer: **16**
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