1+125. 92m Aa16°20' LC1 P.C 13*30 B. Lc2 D. P.T R2
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
Given the compound curve with the vertex V inaccessible, angles A and B are equal to 16°20’ and 13°30’,
respectively. Stationing at B is at 1+125. 92m. Degrees of curve are 3°30’ and 4°00’ for the first and second curve,
respectively. It is desired to substitute the compound curve with a simple curve that shall be tangent to the two tangents, TA and TB, and as well as the common tangent TAB.
-Include illustrations
-Determine the radius of the simple curve and the station the New P.C. and the old P.T.
Transcribed Image Text:1+125. 92m
16°20'
LC1
P.C
13°30
LCz
R1
P.T
R2
B.
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