11:17 %10 Pb+2y=7.5+ 2 * 2.25=12 m RA/P 1.406 m V c√RS 55 1.406 * =2.06 m/s. 1000 Q=AV=16.875 * 2.06= 34.76 m³/s DOOOO Examples: Example 2: A triangular gutter with side slope at angle 60 has a depth 250 mm. If the discharge is 0.04 m3/s. Find the slope of the gutter bed? (c=50) 250 m Examples: Example 3: Design a trapezoidal channel of water having a velocity 0.6 m/s, channel side slope 1:1.5, flow rate 3 m3/s, c=65, hydraulic radius 10 m? Top width = b+2y- Δ Kay О ☐ K
11:17 %10 Pb+2y=7.5+ 2 * 2.25=12 m RA/P 1.406 m V c√RS 55 1.406 * =2.06 m/s. 1000 Q=AV=16.875 * 2.06= 34.76 m³/s DOOOO Examples: Example 2: A triangular gutter with side slope at angle 60 has a depth 250 mm. If the discharge is 0.04 m3/s. Find the slope of the gutter bed? (c=50) 250 m Examples: Example 3: Design a trapezoidal channel of water having a velocity 0.6 m/s, channel side slope 1:1.5, flow rate 3 m3/s, c=65, hydraulic radius 10 m? Top width = b+2y- Δ Kay О ☐ K
Principles of Geotechnical Engineering (MindTap Course List)
9th Edition
ISBN:9781305970939
Author:Braja M. Das, Khaled Sobhan
Publisher:Braja M. Das, Khaled Sobhan
Chapter8: Seepage
Section: Chapter Questions
Problem 8.11P
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ممكن حل سؤالين
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Transcribed Image Text:11:17
%10
Pb+2y=7.5+ 2 * 2.25=12 m
RA/P 1.406 m
V c√RS 55 1.406 * =2.06 m/s.
1000
Q=AV=16.875 * 2.06= 34.76 m³/s
DOOOO
Examples:
Example 2: A triangular gutter with side slope at
angle 60 has a depth 250 mm. If the discharge is 0.04
m3/s. Find the slope of the gutter bed? (c=50)
250 m
Examples:
Example 3: Design a trapezoidal channel of water
having a velocity 0.6 m/s, channel side slope 1:1.5,
flow rate 3 m3/s, c=65, hydraulic radius 10 m?
Top width = b+2y-
Δ
Kay
О
☐
K
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