11111 EXAMPLE: A PERSON STANDING ON THE EDGE OF A HIGH CLIFF THROWS A ROCK STRAIGHT UP WITH AN INITIAL VELOCITY OF 13.0 M/S. THE ROCK MISSES THE EDGE OF THE CLIFF AS IT FALLS BACK TO EARTH. CALCULATE THE POSITION AND VELOCITY OF THE ROCK 1.00 S, 2.00 S, AND 3.00 S AFTER IT IS THROWN, NEGLECTING THE EFFECTS OF AIR RESISTANCE. ALSO CALCULATE THE MAXIMUM HEIGHT OF THE ROCK FROM THE EDGE? WHAT IS THE TIME THAT THE ROCK REACHES TO MAXIMUM HEIGHT? 7.5 Time, t Position, y Velocity, v Acceleration, a 5.0 1.00 s 8.10 m 3.20 m/s -9.80 m/s² 2.00 s 6.40 m -6.60 m/s -9.80 m/s² height (m) 2.5- 0.0- -2.5 3.00 s -5.10 m -16.4 m/s -9.80 m/s² -5.0- Height vs. Time velocity (m/s) 10 5 -5 -10 -15 140 V Velocity vs. Time -7.5- 0.0 0.5 1.0 1.5 time (s) 2.0 2.5 3.0 O 0.0 0.5 1.0 1.5 2.0 2.5 3.0 time (s)

Physics for Scientists and Engineers, Technology Update (No access codes included)
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Chapter4: Motion In Two Dimensions
Section: Chapter Questions
Problem 4.7OQ: A projectile is launched on the Earth with a certain initial velocity and moves without air...
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I need help with this problem and an explanation for the solution described below. (University Physics 1: Kinematics)

11111
EXAMPLE: A PERSON STANDING ON THE EDGE OF A HIGH CLIFF THROWS A ROCK STRAIGHT UP WITH AN INITIAL
VELOCITY OF 13.0 M/S. THE ROCK MISSES THE EDGE OF THE CLIFF AS IT FALLS BACK TO EARTH. CALCULATE THE POSITION
AND VELOCITY OF THE ROCK 1.00 S, 2.00 S, AND 3.00 S AFTER IT IS THROWN, NEGLECTING THE EFFECTS OF AIR
RESISTANCE. ALSO CALCULATE THE MAXIMUM HEIGHT OF THE ROCK FROM THE EDGE? WHAT IS THE TIME THAT THE
ROCK REACHES TO MAXIMUM HEIGHT?
7.5
Time, t Position, y Velocity, v Acceleration, a
5.0
1.00 s
8.10 m
3.20 m/s
-9.80 m/s²
2.00 s
6.40 m
-6.60 m/s
-9.80 m/s²
height (m)
2.5-
0.0-
-2.5
3.00 s
-5.10 m
-16.4 m/s
-9.80 m/s²
-5.0-
Height vs. Time
velocity (m/s)
10
5
-5
-10
-15
140
V
Velocity vs. Time
-7.5-
0.0
0.5
1.0
1.5
time (s)
2.0
2.5
3.0
O
0.0
0.5
1.0
1.5
2.0
2.5
3.0
time (s)
Transcribed Image Text:11111 EXAMPLE: A PERSON STANDING ON THE EDGE OF A HIGH CLIFF THROWS A ROCK STRAIGHT UP WITH AN INITIAL VELOCITY OF 13.0 M/S. THE ROCK MISSES THE EDGE OF THE CLIFF AS IT FALLS BACK TO EARTH. CALCULATE THE POSITION AND VELOCITY OF THE ROCK 1.00 S, 2.00 S, AND 3.00 S AFTER IT IS THROWN, NEGLECTING THE EFFECTS OF AIR RESISTANCE. ALSO CALCULATE THE MAXIMUM HEIGHT OF THE ROCK FROM THE EDGE? WHAT IS THE TIME THAT THE ROCK REACHES TO MAXIMUM HEIGHT? 7.5 Time, t Position, y Velocity, v Acceleration, a 5.0 1.00 s 8.10 m 3.20 m/s -9.80 m/s² 2.00 s 6.40 m -6.60 m/s -9.80 m/s² height (m) 2.5- 0.0- -2.5 3.00 s -5.10 m -16.4 m/s -9.80 m/s² -5.0- Height vs. Time velocity (m/s) 10 5 -5 -10 -15 140 V Velocity vs. Time -7.5- 0.0 0.5 1.0 1.5 time (s) 2.0 2.5 3.0 O 0.0 0.5 1.0 1.5 2.0 2.5 3.0 time (s)
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