1103. A shell leaves a mortar with a muzzle velocity of 500 ft per sec directed upward at 60° with the horizontal. Determine the position of the shell and its resultant velocity 20 sec after firing. How high will it rise? Ans. I 5000 ft; y = 2220 ft; o = 327 ft per see: h=2910 ft 1104
1103. A shell leaves a mortar with a muzzle velocity of 500 ft per sec directed upward at 60° with the horizontal. Determine the position of the shell and its resultant velocity 20 sec after firing. How high will it rise? Ans. I 5000 ft; y = 2220 ft; o = 327 ft per see: h=2910 ft 1104
Glencoe Physics: Principles and Problems, Student Edition
1st Edition
ISBN:9780078807213
Author:Paul W. Zitzewitz
Publisher:Paul W. Zitzewitz
Chapter6: Motion In Two Dimensions
Section6.3: Relative Velocity
Problem 27PP
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![1103. A shell leaves a mortar with a muzzle velocity of 500 ft per sec directed
upward at 60° with the horizontal. Determine the position of the shell and its
resultant velocity 20 sec after firing. How high will it rise?
Ans.
*= 5000 ft; U =
2220 ft; o = 327 ft per sec: h
2910 ft
107
1104](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc4da313f-cff4-4df4-b8a1-dcdbbb0c878f%2Fce54e9b0-b5cd-4aec-ab3a-364dd5b1a3dd%2F7t1l9b_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1103. A shell leaves a mortar with a muzzle velocity of 500 ft per sec directed
upward at 60° with the horizontal. Determine the position of the shell and its
resultant velocity 20 sec after firing. How high will it rise?
Ans.
*= 5000 ft; U =
2220 ft; o = 327 ft per sec: h
2910 ft
107
1104
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