Answered: 11.19 The proportion of observations…

11.19 The proportion of observations from a standard Norm distribution that take values larger than -0.75 is about (a) 0.2266. (b) 0.7734. (c) 0.8023.

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Related questions

Q: The weight of seeds from a certain species of bean follows a normal distribution with mean = 275 mg…

A: The mean of the normal distribution, The standard deviation of the distribution,

Q: Suppose Z follows the standard normal distribution. (a) P(2 1.49) = (c) P (-0.52 < Z<2.10)=

Q: The price-earnings (PE) ratios of a sample of stocks have a mean value of 13.75 and a standard…

A: The empirical rule i.e, 68.2-95.4-99.9P( μ - σ < X < μ + σ ) = 68.2% P( μ - 2σ < X < μ +…

Q: Babies born weighing 2500 grams (about 5.5 pounds) or less are called low-birth-weight babies, and…

A: a. Given:sample mean (x̄)= 2500mean (μ)= 3449standard deviation (σ)=…

Q: Suppose lengths in inches, of adult corn snakes have unkown distribution with mean 62 and standard…

A: Given: Mean of the distribution, μ=62 & standard deviation of the distribution, σ=7…

Q: Suppose the income of workers at your job follows a normal distribution. If you standardize their…

Q: curve and shade the area representing the propo (a) Z ≤ -1.7 (b) Z-1.7 (c) Z> 1.9

A: It is given that the different z-scores. Here, need to find out the proportion according to…

Q: The number of traffic accidents per week at an intersection varies with mean 2.19 and standard…

A: X¯ ~N(μ , σx¯)

Q: Suppose heights, in inches, of male orangutans have an unknown distribution with mean 56 and…

A: According to the central limit theorem,

Q: The mean monthly maximum temperatures for January in Melbourne can be modelled by a Normal…

Q: For a normal populatiln distribution ,the mean with st deviation =1.5,the sample size = 25 and mean…

Q: Suppose x has a normal distribution with mean u = 42 and standard deviation o = 13. Describe the…

A: Mean of the sampling distribution of the sample mean. Standard deviation of the sampling…

Q: The weight of cargo boxes that goes into a certain warehouse follows a normal distribution. A sample…

A: Central limit theorem: For the samples with mean μ and standard deviation σ, as sample size…

Q: In a recent SAT, the mean score for all examinees was 1020. Assume that the distribution of SAT…

Q: 1. What is the z-score of x = 3, if it is 1.1 standard deviations to the left of the mean? (Enter an…

A: Z-score converts individual scores into a standard form. The value of the z-score tells how many…

Q: Suppose that the average and standard deviation of the fine for speeding on a particular highway are…

A: The Normal distribution is also called as the Gaussian distribution. It is the most common…

Q: The price-earnings (PE) ratios of a sample of stocks have a mean value of 14.25 and a standard…

A: Therefore, percentage = 68.26%

Q: Below is a graph of a normal distribution with mean u = -3 and standard deviation O = 3. The shaded…

A: The Z-score of a random variable X is defined as follows: Z = (X – µ)/σ. Here, µ and σ are the mean…

Q: ppose x comes from a distribution where the mean is 151 and the standard deviation is 22. Suppose a…

A: Population mean =151Population standard deviation =22Sample size n =63

Q: The average height of an adult male is 64.8" with a standard deviation of 1.58". Calculate an…

A: The average height of an adult male is 64.8" with a standard deviation of 1.58".

Q: Suppose you have a set of observations that follow a normal distribution with a mean μ and…

A: Solution-: Let, X= be the random variable Given: mean=μ,SD=σ We find, (a) P[X-μ<1.75σ]=? (b)…

Q: Suppose a simple random sample of size n=81 is obtained from a population with a mean of 88 and a…

A: Given sample of size n=81 mean=88 standard deviation =27.

Q: The mean monthly maximum temperatures for January in Canberra can be modelled by a Normal…

A: We have to find given probability..

Q: The standard deviation for all SAT scores is 72.3. A random sample of 57 tests has a(n) average…

A: Null hypothesis: µ=1352. Alternative hypothesis: µ≠1352. Here, the sample mean, is 1393. Population…

Q: Consider the normal distribution with mean 63 and standard deviation 6. Find the area under the…

Q: What is the approximnate probability that there are fewer than 100 accidents at the intersection in…

A: Given that. X~N( μ , ?^2 ) μ=2.2 , ?=1.4 Z-score =( x - μ )/?

Q: We plotted the sampling distribution of the mean from 200 samples of size 5 from the population of…

Q: A Normal distribution has mean µ = 21 and standard deviation ở = 3.2. Find the z-score for the…

A: Mean(μ)=21standard deviation(σ)=3.2

Q: 6.8 Given a normal distribution with μ = 30 and σ = 6, find (a) the normal curve area to the right…

A: Given that X~Normal(μ=30, σ=6) Note: According to bartelby question answer guidelines an expert can…

Q: Consider a positive number $a$. Which respect to the standard normal distribution, which of the…

A: Since you have asked multiple questions, we will solve the first question for you. If you want any…

Q: (a) What percent of tablets are subject to a force that meets the sp (b) The manufacturer adjusts…

A: here mean = 11.5 standard deviation = 0.2 here use standard normal table for probability from…

Q: An ecologist is studying the impact of local polluted waters on the growth of alligators. The length…

A: Length of adult male alligators follows a normal distribution with µ and standard deviation 2. n…

Q: in a normal distribution with the mean of 15 and standard deviation of 3 what does a z score of -2…

A: Given : A normal distribution with Mean (μ) = 15 Standard deviation (σ) = 3 z-score = -2

Q: 2. The general weighted average of Mechanical Engineering students from a certain class are…

A: We have given that. X~N( μ , ?^2 ) μ = 1.65 , ? = 0.9 Z-score =( x - μ )/?

Q: The length of a fully grown hibiscus plant has a mean 35cm. It is found that 5% of these plants are…

A: Given that μ=35 Given that 5% of the plants are longer than 45 cm. That is,…

Q: The average grade in an exam is 68 and the standard deviation is 8. A grade (C) will be given…

Q: 6.2 The Standard Normal Distribution Table: Z-score and Probability A company produces steel rods.…

A: To find the probability that the length of a randomly selected steel rod is greater than 167.7 cm,…

Q: Find the probability that a randomly selected district had fewer than 1,700 votes for this…

A: Given that, In a certain presidential election, Alaska's 40 election districts averaged 1,958.8…

Q: The overhead reach distances of adult females are normally distributed with a mean of 195 cm and a…

Question

11.19 The proportion of observations from a standard Norm
distribution that take values larger than -0.75 is about
(a) 0.2266.
(b) 0.7734.
(c) 0.8023.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

$Statistical Power and Errors$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, probability and related others by exploring similar questions and additional content below.

Similar questions

3. 4. Find the area under the shaded region. The graph depicts the standard normal distribution with mean 0 and standard devlation 1. - 2.36 00.0091 0.9909 O 0.5 01 Continue 2021 McGraw-Hill Education. All Rights Resen SAMSUNG 21
10..
The average grade in an exam is (65 + N) and the standard deviation is 8. A grade (C) will be given between 45% and 64% of the grades received by the students. Find the required grade for the student to get (C). (Assume that the distribution of the notes is normally distributed.)
Suppose a normal distribution has a mean of 79 and a standard deviation of 7. What is P(x < 65)? A. 0.975 В. 0.84 С. 0.025 D. 0.16
Suppose heights, in inches, of male orangutans have an unknown distribution with mean 60 and standard deviation 3 inches. A sample of size n = 49 is randomly taken from the population and the mean is taken. Using the Central Limit Theorem for Means, what is the sample mean distribution?
Compute for the mean (??̅) and standard deviation (??̅) of the sampling distribution of the sample means and compare these to the mean and standard deviation of the population.
10) A county is considering raising the speed limit on a road because they claim that the mean speed of vehicles is greater than 40 mi/hr. A random sample of 15 vehicles has a mean speed of 43 mil/hr and a standard deviation of 4.4 mi/hr. Assume that speeds follow a normal distribution. What statistical test should be used to test the claim? (pick one of the options) 1. t-test 2. 2.73 3. 15 4. 10.9 5. 14 6. z-test 7. 2.52 8. 2.64 Calculate the value of standardized test statistic. (pick one of the options) 1. t-test 2. 2.73 3. 15 4. 10.9 5. 14 6. z-test 7. 2.52 8. 2.64 What is the degree of the freedom for the distribution of the test statistics. (pick one of the options) 1. t-test 2. 2.73 3. 15 4. 10.9 5. 14 6. z-test 7. 2.52 8. 2.64
4. Let X be a random variable representing dividend yield of Australian bank stocks. We may assume that X has a normal distribution with standard deviation = 2.4%. A random sample of 19 Australian bank stocks has a sample mean of = 8.71%. For the entire Australian stock market, the mean dividend yield is = 5.9%. Do these data indicate that the dividend yield of all Australian bank stocks is higher than 5.9% ? Use Q=.05. Are the data statistically significant at the given level of significance? Based on your answers, will you reject or fail to reject the null hypothesis? A. The p-value is less than the level of significance and so the data are not statistically significant. Thus, we reject the null hypothesis. B. The p-value is less than the level of significance and so the data are statistically significant. Thus, we fail to reject the null hypothesis. C. The p-value is greater than the level of significance and so the data are statistically significant. Thus, we fail to reject the…
Q2) A certain machine makes electrical resistors having a mean resistance of 60 ohms and a standard deviation of 2 ohms. Assuming that the resistance follows a normal distribution and can be measured to any degree of accuracy, what percentage of resistors will have a resistance exceeding 63 ohms?
Assume all populations are normally distributed. A travel analyst claims that the mean price of a round trip flight from New York City to Los Angeles is less than $507. In a random sample of 55 round trip flights from NYC to LA, the mean price is $502. Assume the population standard deviation is $111. At α = 0.05, is there enough evidence to support the travel analyst’s claim?
Suppose that the distribution of scores on an exam can be described by a normal curve with mean 110. The 16th percentile of this distribution is 80. (Use the Empirical Rule.) (a) What is the 84th percentile? (b) What is the approximate value of the standard deviation of exam scores? (c) What z score is associated with an exam score of 125? (d) What percentile corresponds to an exam score of 170? (e) Do you think there were many scores below 20? Explain. A score of 20 is? standard deviations below the mean, and so the percentage of scores below 20 would be approximately ... how many percentage