11. Suppose the soil beneath the footing is now a sand with average SPT N60 of 28 (see below). Predict the footing settlement (in inches) using Meyerhof's formulas. 2 ft 18 ft 6 ft P = 72 kips Sand, y = 118 pcf Sand N60 = 28 Gravel
11. Suppose the soil beneath the footing is now a sand with average SPT N60 of 28 (see below). Predict the footing settlement (in inches) using Meyerhof's formulas. 2 ft 18 ft 6 ft P = 72 kips Sand, y = 118 pcf Sand N60 = 28 Gravel
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:### Example Problem for Predicting Footing Settlement Using Meyerhof’s Formulas
**Problem Statement:**
Suppose the soil beneath the footing is now a sand with an average Standard Penetration Test (SPT) \( N_{60} \) of 28. Predict the footing settlement (in inches) using Meyerhof’s formulas.
**Diagram Explanation:**
- The diagram represents a cross-section of a soil profile beneath a footing.
- There is a vertical load \( P = 72 \) kips acting downward on the footing.
- Dimensions of the footing are 6 feet wide and situated 2 feet below the ground surface.
- The top layer under the footing is sand with a unit weight \( \gamma = 118 \) pounds per cubic foot (pcf), and an \( N_{60} \) value of 28.
- The sandy layer has a depth of 18 feet before transitioning to a gravel layer.
**Key Parameters in Diagram:**
- **Load (P):** 72 kips
- **Footing Width:** 6 ft
- **Depth to Sand Layer:** 2 ft
- **Depth of Sand Layer:** 18 ft
- **Unit Weight of Sand (γ):** 118 pcf
- **SPT N-Value for Sand (N60):** 28
- **Underlying Material:** Gravel
This problem involves calculating the expected settlement of the footing using Meyerhof’s empirical formulas, taking into account the characteristics and depth of the sand layer directly beneath the foundation.
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