11. Suppose the soil beneath the footing is now a sand with average SPT N60 of 28 (see below). Predict the footing settlement (in inches) using Meyerhof's formulas. 2 ft 18 ft 6 ft P = 72 kips Sand, y = 118 pcf Sand N60 = 28 Gravel

Structural Analysis
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Author:KASSIMALI, Aslam.
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Chapter2: Loads On Structures
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### Example Problem for Predicting Footing Settlement Using Meyerhof’s Formulas

**Problem Statement:**
Suppose the soil beneath the footing is now a sand with an average Standard Penetration Test (SPT) \( N_{60} \) of 28. Predict the footing settlement (in inches) using Meyerhof’s formulas.

**Diagram Explanation:**

- The diagram represents a cross-section of a soil profile beneath a footing.
- There is a vertical load \( P = 72 \) kips acting downward on the footing.
- Dimensions of the footing are 6 feet wide and situated 2 feet below the ground surface.
- The top layer under the footing is sand with a unit weight \( \gamma = 118 \) pounds per cubic foot (pcf), and an \( N_{60} \) value of 28.
- The sandy layer has a depth of 18 feet before transitioning to a gravel layer.

**Key Parameters in Diagram:**

- **Load (P):** 72 kips
- **Footing Width:** 6 ft
- **Depth to Sand Layer:** 2 ft
- **Depth of Sand Layer:** 18 ft
- **Unit Weight of Sand (γ):** 118 pcf
- **SPT N-Value for Sand (N60):** 28
- **Underlying Material:** Gravel

This problem involves calculating the expected settlement of the footing using Meyerhof’s empirical formulas, taking into account the characteristics and depth of the sand layer directly beneath the foundation.
Transcribed Image Text:### Example Problem for Predicting Footing Settlement Using Meyerhof’s Formulas **Problem Statement:** Suppose the soil beneath the footing is now a sand with an average Standard Penetration Test (SPT) \( N_{60} \) of 28. Predict the footing settlement (in inches) using Meyerhof’s formulas. **Diagram Explanation:** - The diagram represents a cross-section of a soil profile beneath a footing. - There is a vertical load \( P = 72 \) kips acting downward on the footing. - Dimensions of the footing are 6 feet wide and situated 2 feet below the ground surface. - The top layer under the footing is sand with a unit weight \( \gamma = 118 \) pounds per cubic foot (pcf), and an \( N_{60} \) value of 28. - The sandy layer has a depth of 18 feet before transitioning to a gravel layer. **Key Parameters in Diagram:** - **Load (P):** 72 kips - **Footing Width:** 6 ft - **Depth to Sand Layer:** 2 ft - **Depth of Sand Layer:** 18 ft - **Unit Weight of Sand (γ):** 118 pcf - **SPT N-Value for Sand (N60):** 28 - **Underlying Material:** Gravel This problem involves calculating the expected settlement of the footing using Meyerhof’s empirical formulas, taking into account the characteristics and depth of the sand layer directly beneath the foundation.
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