11. Propose a mechanism, using curved arrows to show electron movement for each step. fr a) CH, CH= CIĘ t HBr CH CH CH le Light b) CH, Cr C + Cle ( show the initiation, propagation and termi nation steps) >CHH Crb CH2CI + HCI C) Bra > HO- -Br CHs + H,0 S0g cataly st H;C - C- + H20 + Br, Ccla "Br L (len) CH3 CH- CH2 -> H A) CH CH CH2 t H-5r -> (Mue Susstitu ed) CH3 CH CHT エエ
11. Propose a mechanism, using curved arrows to show electron movement for each step. fr a) CH, CH= CIĘ t HBr CH CH CH le Light b) CH, Cr C + Cle ( show the initiation, propagation and termi nation steps) >CHH Crb CH2CI + HCI C) Bra > HO- -Br CHs + H,0 S0g cataly st H;C - C- + H20 + Br, Ccla "Br L (len) CH3 CH- CH2 -> H A) CH CH CH2 t H-5r -> (Mue Susstitu ed) CH3 CH CHT エエ
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Title: Organic Reaction Mechanisms**
1. **Problem Statement:**
Propose a mechanism, using curved arrows to show electron movement for each step.
2. **Reactions:**
a) **Reaction:**
\[
\text{CH}_3\text{CH} = \text{CH}_2 + \text{HBr} \rightarrow \text{CH}_3\text{CHBrCH}_3
\]
b) **Reaction:**
\[
\text{CH}_3\text{CH}_2\text{CH}_3 + \text{Cl}_2 \xrightarrow{\text{Light}} \text{CH}_3\text{CH}_2\text{CH}_2\text{Cl} + \text{HCl}
\]
Show the initiation, propagation, and termination steps.
c) **Reaction:**
\[
\begin{align*}
&\text{Cyclohexene + Br}_2 \xrightarrow{\text{H}_2\text{O}} \rightarrow \text{Bromohydrin}
\end{align*}
\]
d) **Reaction:**
\[
\begin{align*}
&\text{CH}_3\text{C}\equiv\text{CH} + \text{H}_2\text{O} \xrightarrow{\text{H}_2\text{SO}_4 \text{ catalyst}} \rightarrow \text{CH}_3\text{C(OH)}=\text{CH}_2
\end{align*}
\]
e) **Reaction:**
\[
\begin{align*}
&\text{Cyclopentadiene + Br}_2 \xrightarrow{\text{CH}_2\text{Cl}_2} \rightarrow \text{Brominated compound}
\end{align*}
\]
3. **Mechanism Graph Explanation:**
- **Graph A Explanation:**
- **Step 1:** The double bond in CH₃CH=CH₂ attacks the H⁺ in HBr, forming a more stable carbocation intermediate.
- **Step 2:** The Br⁻ ion attacks the carbocation, leading to the formation of CH₃CHBrCH₃.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9d249cdd-7458-4d80-bc19-9ab6eb581b5b%2Fcbc2cfb6-b5ee-4c75-8271-41a2f28f576f%2F1sqm049_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Title: Organic Reaction Mechanisms**
1. **Problem Statement:**
Propose a mechanism, using curved arrows to show electron movement for each step.
2. **Reactions:**
a) **Reaction:**
\[
\text{CH}_3\text{CH} = \text{CH}_2 + \text{HBr} \rightarrow \text{CH}_3\text{CHBrCH}_3
\]
b) **Reaction:**
\[
\text{CH}_3\text{CH}_2\text{CH}_3 + \text{Cl}_2 \xrightarrow{\text{Light}} \text{CH}_3\text{CH}_2\text{CH}_2\text{Cl} + \text{HCl}
\]
Show the initiation, propagation, and termination steps.
c) **Reaction:**
\[
\begin{align*}
&\text{Cyclohexene + Br}_2 \xrightarrow{\text{H}_2\text{O}} \rightarrow \text{Bromohydrin}
\end{align*}
\]
d) **Reaction:**
\[
\begin{align*}
&\text{CH}_3\text{C}\equiv\text{CH} + \text{H}_2\text{O} \xrightarrow{\text{H}_2\text{SO}_4 \text{ catalyst}} \rightarrow \text{CH}_3\text{C(OH)}=\text{CH}_2
\end{align*}
\]
e) **Reaction:**
\[
\begin{align*}
&\text{Cyclopentadiene + Br}_2 \xrightarrow{\text{CH}_2\text{Cl}_2} \rightarrow \text{Brominated compound}
\end{align*}
\]
3. **Mechanism Graph Explanation:**
- **Graph A Explanation:**
- **Step 1:** The double bond in CH₃CH=CH₂ attacks the H⁺ in HBr, forming a more stable carbocation intermediate.
- **Step 2:** The Br⁻ ion attacks the carbocation, leading to the formation of CH₃CHBrCH₃.
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