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11. In this problem you need to simulate part of a Yahtzee game. This turns out to be more complicated than I expected. To solve it, l created a dictionary (I called it "count") where the key is the number on the die and the value is the number of times that number is rolled. So, if you roll a Yahtzee of 3's, your dictionary would have the single entry count[3] = 5. You can get a list of the keys by using keys = list(count.keys()) and a list of the values using values = list(count.values()). With these, you can use the Wikipedia entry to logic things out. If there is a 5 in values, for instance, you have a Yahtzee; a 4 means you have 4 of a kind; a 3 is three of a kind if there is no 2, otherwise, it is a Full House. To get the straights, use the information in the boxes on the Wikipedia entry - if len(values) == 5, you have five different die values, but it's only a large straight if you're missing either a 1 or a 6. The small straight is a bit more complicated but similar. After you find all these, calculate the chance score as the sum of the rolls - then return either a score you've already calculated or the chance value, whichever is larger. Wheh!

11. In this problem you need to simulate part of a Yahtzee game. This turns out to be more complicated than I expected. To solve it, l created a dictionary (I called it "count") where the key is the number on the die and the value is the number of times that number is rolled. So, if you roll a Yahtzee of 3's, your dictionary would have the single entry count[3] = 5. You can get a list of the keys by using keys = list(count.keys()) and a list of the values using values = list(count.values()). With these, you can use the Wikipedia entry to logic things out. If there is a 5 in values, for instance, you have a Yahtzee; a 4 means you have 4 of a kind; a 3 is three of a kind if there is no 2, otherwise, it is a Full House. To get the straights, use the information in the boxes on the Wikipedia entry - if len(values) == 5, you have five different die values, but it's only a large straight if you're missing either a 1 or a 6. The small straight is a bit more complicated but similar. After you find all these, calculate the chance score as the sum of the rolls - then return either a score you've already calculated or the chance value, whichever is larger. Wheh!

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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I need help on my python assignment. The first screenshot is the question being asked and the second screenshot is of some hints that were given to us. 

11. In this problem you need to simulate part of a Yahtzee game. This turns out to be more complicated than I expected. To solve it, I created a dictionary (I called it "count") where the key is the number on the die and the value is the number of times that number is rolled. So, if you roll a Yahtzee of 3's, your dictionary would have the single entry count[3] = 5. You can get a list of the keys by using keys = list(count.keys()) and a list of the values using values = list(count.values()). With these, you can use the Wikipedia entry to logic things out. If there is a 5 in values, for instance, you have a Yahtzee; a 4 means you have 4 of a kind; a 3 is three of a kind if there is no 2, otherwise, it is a Full House. To get the straights, use the information in the boxes on the Wikipedia entry - if len(values) == 5, you have five different die values, but it's only a large straight if you're missing either a 1 or a 6. The small straight is a bit more complicated but similar. After you find all these, calculate the chance score as the sum of the rolls - then return either a score you've already calculated or the chance value, whichever is larger. Wheh!
Transcribed Image Text:11. In this problem you need to simulate part of a Yahtzee game. This turns out to be more complicated than I expected. To solve it, I created a dictionary (I called it "count") where the key is the number on the die and the value is the number of times that number is rolled. So, if you roll a Yahtzee of 3's, your dictionary would have the single entry count[3] = 5. You can get a list of the keys by using keys = list(count.keys()) and a list of the values using values = list(count.values()). With these, you can use the Wikipedia entry to logic things out. If there is a 5 in values, for instance, you have a Yahtzee; a 4 means you have 4 of a kind; a 3 is three of a kind if there is no 2, otherwise, it is a Full House. To get the straights, use the information in the boxes on the Wikipedia entry - if len(values) == 5, you have five different die values, but it's only a large straight if you're missing either a 1 or a 6. The small straight is a bit more complicated but similar. After you find all these, calculate the chance score as the sum of the rolls - then return either a score you've already calculated or the chance value, whichever is larger. Wheh!
11. Write a function that simulates the rolling of 5 dice at a time. Calculate and print the highest possible score of the five dice using the lower section of the game "Yatzee".
Transcribed Image Text:11. Write a function that simulates the rolling of 5 dice at a time. Calculate and print the highest possible score of the five dice using the lower section of the game "Yatzee".
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