11. If the original 24 m edge length x of a cube decreases at the rate of 5 m/min, when x = 3 m at what rate does the cube's a. surface area change? h yolume change? a bns
11. If the original 24 m edge length x of a cube decreases at the rate of 5 m/min, when x = 3 m at what rate does the cube's a. surface area change? h yolume change? a bns
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
Related questions
Question
Can you please solve number 11
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instructi
21
84
up
•4
ip
as the rate at which the weight is being raised wher
प
syllabus
tudent
EXERCISES 3.10
purse, a
e returr
1. Area Suppose that the radius r and area A
differentiable functions of t. Write an equation that relates dA/ dt
to dr/dt.
Tr² of a circle are
%3D
a. How is dV |dt
stem
b. How is dV| dt
Suppose that the radius r and surface area
2. Surface area
S = 4r2 of a sphere are differentiable functions of t. Write an
c. How is dV|d
ww.m
constant?
equation that relates dS/dt to dr/dt.
14. Volume The:
3. Assume that y
related to the co
5x and dx/dt = 2. Find dy/dt.
4. Assume that 2x + 3y = 12 and dy/dt = -2. Find dx/dt.
a. How is dV
%3D
%3D
5. If y = x² and dx/dt = 3, then what is dy/dt when x = -1?
b. How is dV
%3D
c. How is d\
6. If x = y3 – y and dy/dt = 5, then what is dx/dt when y = 2?
%3D
%3D
constant?
7. If x2 + y = 25 and dx/dt = -2, then what is dy/ dt when
x = 3 and y = -4?
15. Changing v
%3D
and resistan
8. If xy3 = 4/27 and dy/dt = 1/2, then what is dx/dt when
here are rE
increasing
rate of 1/3
x = 2?
9. If L = Vx² + y², dx/dt = -1, and dy/dt = 3, find dL/dt
= 12.
%3D
ea
when x = 5 and
%3D
10. If r + s? + v³ = 12, dr/dt = 4, and ds/dt = -3, find dv/dt
when r =
3 and s = 1.
%3D
%3D
11. If the original 24 m edge length x of a cube decreases at the rate
of 5 m/min, when x = 3 m at what rate does the cube's
%3D
a. surface area change?
a. Wh
b. volume change? t
b. W
12. A cube's surface area increases at the rate of 72 in² / sec. At what
rate is the cube's volume changing when the edge length is x = 3 in?
C. W
d. F
13. Volume The radius r and height h of a right circular cylinder
are related to the cylinder's volume V by the formula V = arh."
Transcribed Image Text:instruct
instructi
21
84
up
•4
ip
as the rate at which the weight is being raised wher
प
syllabus
tudent
EXERCISES 3.10
purse, a
e returr
1. Area Suppose that the radius r and area A
differentiable functions of t. Write an equation that relates dA/ dt
to dr/dt.
Tr² of a circle are
%3D
a. How is dV |dt
stem
b. How is dV| dt
Suppose that the radius r and surface area
2. Surface area
S = 4r2 of a sphere are differentiable functions of t. Write an
c. How is dV|d
ww.m
constant?
equation that relates dS/dt to dr/dt.
14. Volume The:
3. Assume that y
related to the co
5x and dx/dt = 2. Find dy/dt.
4. Assume that 2x + 3y = 12 and dy/dt = -2. Find dx/dt.
a. How is dV
%3D
%3D
5. If y = x² and dx/dt = 3, then what is dy/dt when x = -1?
b. How is dV
%3D
c. How is d\
6. If x = y3 – y and dy/dt = 5, then what is dx/dt when y = 2?
%3D
%3D
constant?
7. If x2 + y = 25 and dx/dt = -2, then what is dy/ dt when
x = 3 and y = -4?
15. Changing v
%3D
and resistan
8. If xy3 = 4/27 and dy/dt = 1/2, then what is dx/dt when
here are rE
increasing
rate of 1/3
x = 2?
9. If L = Vx² + y², dx/dt = -1, and dy/dt = 3, find dL/dt
= 12.
%3D
ea
when x = 5 and
%3D
10. If r + s? + v³ = 12, dr/dt = 4, and ds/dt = -3, find dv/dt
when r =
3 and s = 1.
%3D
%3D
11. If the original 24 m edge length x of a cube decreases at the rate
of 5 m/min, when x = 3 m at what rate does the cube's
%3D
a. surface area change?
a. Wh
b. volume change? t
b. W
12. A cube's surface area increases at the rate of 72 in² / sec. At what
rate is the cube's volume changing when the edge length is x = 3 in?
C. W
d. F
13. Volume The radius r and height h of a right circular cylinder
are related to the cylinder's volume V by the formula V = arh.
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