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11. Given x = 1 + t, y = 6, z = 3t + 7, the direction vector of the line is: a. (1, 0, – 3) b. (1, 6, 7) c. (5, 4, 3) x+2 12. Given *+² = = 27, the direction vector of the lines : a. (2,0,- 7) b. (3,- 5, 2) c. (5, 4, 4) d. (0, 0, 1) d. (1, 0, 0)

11. Given x = 1 + t, y = 6, z = 3t + 7, the direction vector of the line is: a. (1, 0, – 3) b. (1, 6, 7) c. (5, 4, 3) x+2 12. Given *+² = = 27, the direction vector of the lines : a. (2,0,- 7) b. (3,- 5, 2) c. (5, 4, 4) d. (0, 0, 1) d. (1, 0, 0)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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11. Given x = 1 + t, y = 6, z = 3t + 7, the direction vector of the line is: a. (1, 0, -3) b. (1, 6, 7) c. (5, 4, 3) Z-7 12. Given x+2 3 = = 227, the direction vector of the lines : -5 a. (2, 0, - 7) b. (3, — 5, 2) c. (5, 4, 4) d. (0, 0, 1) d. (1, 0, 0)
Transcribed Image Text:11. Given x = 1 + t, y = 6, z = 3t + 7, the direction vector of the line is: a. (1, 0, -3) b. (1, 6, 7) c. (5, 4, 3) Z-7 12. Given x+2 3 = = 227, the direction vector of the lines : -5 a. (2, 0, - 7) b. (3, — 5, 2) c. (5, 4, 4) d. (0, 0, 1) d. (1, 0, 0)
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