11. Given the information provided in Fig. 124, determine: а. В. b. Vcc- c. Rg. Vcc 20 μΑ !. 2.7 k 2 RB + B VCE = 7.3 V o 2.1 V 0.68 kN

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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2. The answer is already given. I want you to explain them in plain English.

BJT Biasing

VE 2.1 V
(a) Ic= Ig =
RE
11.
= 3.09 mA
0.68 k2
I. 3.09 mA
B=
Is
= 154.5
20 μΑ
(b) Vcc = VR. + VCE + VE
= (3.09 mA)(2.7 k2) + 7.3 V + 2.1 V = 8.34 V + 7.3 V + 2.1 v
= 17.74 V
VR Vcc - VRE – Vg _ 17.74 V – 0.7 V – 2.1 V
(c) Rg =
20 μΑ
14.94 V
= 747 kQ
20 μΑ
Transcribed Image Text:VE 2.1 V (a) Ic= Ig = RE 11. = 3.09 mA 0.68 k2 I. 3.09 mA B= Is = 154.5 20 μΑ (b) Vcc = VR. + VCE + VE = (3.09 mA)(2.7 k2) + 7.3 V + 2.1 V = 8.34 V + 7.3 V + 2.1 v = 17.74 V VR Vcc - VRE – Vg _ 17.74 V – 0.7 V – 2.1 V (c) Rg = 20 μΑ 14.94 V = 747 kQ 20 μΑ
11. Given the information provided in Fig. 124, determine:
а. В.
b. Vcc-
с. Rв-
Vcc
20 μΑ
2.7 k 2
RB
+ B
VCE =7.3 V
o 2.1 V
'0.68 kN
FIG. 124
Transcribed Image Text:11. Given the information provided in Fig. 124, determine: а. В. b. Vcc- с. Rв- Vcc 20 μΑ 2.7 k 2 RB + B VCE =7.3 V o 2.1 V '0.68 kN FIG. 124
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