11. Given :Number of pairs of observation X and Y series = 8X series Arithmetic Average = 74.5X series Assumed Average = 69.0X series Standard Deviation = 13.07Y series Arithmetic Average = 125.5Y series Assumed Average = 112Y series Standard Deviation = 15.85Summation of products of corresponding deviations of X and Y series = 2,176, Calculate thecoefficient of correlation.E dx dy - N (X- Ax) (Y- Ay)Ν σx σy

Formula to calculate coefficient of correlation is given If we simply put the provided values in…

Answered: 11. Given : Number of pairs of…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Please do not give solution in image formate thanku. i am stuck on this question.. You run a regression analysis on a bivariate set of data ( n = 34 ). You obtain the regression equation y = - 2.112 x + 59.334 with a correlation coefficient of r = - 0.878 (which is significant at α = 0.01 ). You want to predict what value (on average) for the explanatory variable will give you a value of 70 on the response variable. What is the predicted explanatory value? x = (Report answer accurate to one decimal place.)
N= 150 observations were collected on a time series that was identified as a AR(2) time series. The following statistics were computed from the data. Mean - 45.0 Variance 15.6 Autocorrelation function (up to lag 5) r1 = 0.80, r2 = .50, rз = .26, r4 = -.10, rs = 0.08: == Estimate the parameters of the model using the method of moments.
From the following data calculate (i) Correlation coefficient (ü) Standard Deviation of Y (Gy) X=-85 Y Y= 89 X Gz=3
Q5 Find the variance for the PDF px(x) = e-«/2, x > 0.
a b Absolute standard deviation = Coefficient of variation = y = 1.20 (+0.02) x 10-8-3.60(±0.2) × 10-⁹ x Result = Absolute standard deviation = Coefficient of variation = C Result = d y=90.95 (±0.08) - 89.40(±0.06) +0.200(+0.004) Absolute standard deviation == Coefficient of variation = Result = ± y= y = 0.0040 (+0.0005) x 10.28 (+0.02) × 395(+1) Result = ± Absolute standard deviation = Coefficient of variation = % 329(+0.03) x 10-14 1.47 (+0.04) x 10-16 % % H % ±
10. You estimated a regression with the following output. Source | SS df MS Number of obs = 333 -------------+---------------------------------- F(1, 331) = 4608.21 Model | 32636494.1 1 32636494.1 Prob > F = 0.0000 Residual | 2344225.8 331 7082.25316 R-squared = 0.9330 -------------+---------------------------------- Adj R-squared = 0.9328 Total | 34980719.9 332 105363.614 Root MSE = 84.156 ------------------------------------------------------------------------------ Y | Coef. Std. Err. t P>|t| [95% Conf. Interval] -------------+---------------------------------------------------------------- X | 30.79902 .4537022 67.88 0.000 29.90652 31.69153 _cons | 20.85313 42.1964 0.49 0.621 -62.1538 103.8601…
The amounts of 6 restaurant bills and the corresponding amounts of the tips are given in the below. Assume that bill amount is the explanatory variable and tip amount the response variable. Bill 32.98 49.72 52.44 64.30 97.34 88.01 Tip 4.50 5.28 7.00 7.70 16.00 10.00 (a) Find the correlation: r= (c) The regression equation is y^= . (d) If the amount of the bill is $90, the best prediction for the amount of the tip is $ .Note: Enter your answer as a number xx.xx (e) According to the regression equation, for every $5 increase in the bill, the tip should INCREASE or DECREASE) by $ .
For the data shown to the right, determine the linear.correlation coefficient using the formulas shown below. Compare your answers in part (a) and (b). 3 5 2| 1| 0 |-1-2 y a. Use the definition r= SySy Exy - (Ex)(E»)/n b. Use the computing formula r= a. Using the definition, r= (Round to three decimal places as needed.)
If X is a normal variate with mean 18 and variance 625, find P(-31 18 ). 1 1.96 [ Given f- dt = 0.9750021 }
Hello. I am having a hard time understanding and solving this problem. Can I ask for help how? Here is the problem. The director of an alumni association for a small college wants to determine whether there is any type of relationship between the amount of an alumnus’s contribution (in dollars) and the number of years the alumnus has been out of school. The data follow. Solve the correlation r and find the y’ when x = 4 years. I have also attached the image of the correlation data.
please do this urgently
If 0 is the angle between the two regression lines. Show that sin 0 < 1 - r? (r is the correlation coefficient )

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