11. Find the area of the Shaded circle segment Rond to the nearest tenth 120° No acm

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
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**Problem 11: Finding the Area of a Shaded Circle Segment**

**Objective:**
Determine the area of the shaded segment of a circle. Round the answer to the nearest tenth.

**Diagram Description:**
- A circle is illustrated with center \( O \).
- Two radii \( OM \) and \( OL \) intersect the circle, creating a sector \( MOL \).
- The angle between the two radii \( OM \) and \( OL \) is labeled as \( 120^\circ \).
- The radius of the circle is given as \( 9 \) cm.
- The area of the sector \( MOL \) is partially shaded.

**Steps to Find the Area of the Shaded Segment:**
1. **Calculate the Area of the Sector:**
   The area of the sector with angle \( \theta \) (in degrees) is given by the formula:
   \[
   \text{Area of sector} = \pi r^2 \left(\frac{\theta}{360}\right)
   \]
   In this problem:
   \[
   r = 9 \text{ cm}, \quad \theta = 120^\circ
   \]
   Thus, the area of the sector \( MOL \):
   \[
   \text{Area of sector} = \pi (9)^2 \left(\frac{120}{360}\right)
   \]
   Simplify:
   \[
   \text{Area of sector} = \pi (81) \left(\frac{1}{3}\right) = 27\pi \text{ cm}^2
   \]

2. **Calculate the Area of the Triangular Portion \( \Delta MOL \):**
   The area of the triangle can be found using trigonometric relationships or by using the formula for the area of a triangle when two sides and the included angle are known. Given the radius is \( 9 \) cm and the included angle is \( 120^\circ \):
   \[
   \text{Area of } \Delta MOL = \frac{1}{2} r^2 \sin(\theta)
   \]
   Substitute \( r = 9 \text{ cm}, \quad \theta = 120^\circ \):
   \[
   \text{Area of } \Delta MOL = \frac{1}{2} (9)^2 \sin(120^\circ)
   \
Transcribed Image Text:**Problem 11: Finding the Area of a Shaded Circle Segment** **Objective:** Determine the area of the shaded segment of a circle. Round the answer to the nearest tenth. **Diagram Description:** - A circle is illustrated with center \( O \). - Two radii \( OM \) and \( OL \) intersect the circle, creating a sector \( MOL \). - The angle between the two radii \( OM \) and \( OL \) is labeled as \( 120^\circ \). - The radius of the circle is given as \( 9 \) cm. - The area of the sector \( MOL \) is partially shaded. **Steps to Find the Area of the Shaded Segment:** 1. **Calculate the Area of the Sector:** The area of the sector with angle \( \theta \) (in degrees) is given by the formula: \[ \text{Area of sector} = \pi r^2 \left(\frac{\theta}{360}\right) \] In this problem: \[ r = 9 \text{ cm}, \quad \theta = 120^\circ \] Thus, the area of the sector \( MOL \): \[ \text{Area of sector} = \pi (9)^2 \left(\frac{120}{360}\right) \] Simplify: \[ \text{Area of sector} = \pi (81) \left(\frac{1}{3}\right) = 27\pi \text{ cm}^2 \] 2. **Calculate the Area of the Triangular Portion \( \Delta MOL \):** The area of the triangle can be found using trigonometric relationships or by using the formula for the area of a triangle when two sides and the included angle are known. Given the radius is \( 9 \) cm and the included angle is \( 120^\circ \): \[ \text{Area of } \Delta MOL = \frac{1}{2} r^2 \sin(\theta) \] Substitute \( r = 9 \text{ cm}, \quad \theta = 120^\circ \): \[ \text{Area of } \Delta MOL = \frac{1}{2} (9)^2 \sin(120^\circ) \
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