Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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
Transcribed Image Text:**Problems and Solutions**
**7. Problem Statement:**
The wavelength of green light from a traffic signal is centered at 5.20 x 10⁻⁵ cm. Calculate the frequency of this light.
- Note: Convert cm to m.
- 1m = 100cm
**Solution Steps:**
- Convert wavelength to meters: \( \text{wavelength} = 5.20 \times 10^{-5} \text{ cm} = 5.20 \times 10^{-7} \text{ m} \)
- Use the formula: \( v = \frac{c}{\lambda} \)
- Calculation: \( v = \frac{3 \times 10^8 \text{ m/s}}{5.20 \times 10^{-7} \text{ m}} = 5.77 \times 10^{14} \text{ Hz} \)
**8. Problem Statement:**
Calculate the frequency of light that has a wavelength of 425nm. Identify the type of electromagnetic radiation.
- Note: \( 1\text{nm} = 1 \times 10^{-9} \text{m} \)
**Solution Steps:**
- Convert: \( \text{wavelength} = 425 \text{ nm} = 425 \times 10^{-9} \text{ m} = 4.25 \times 10^{-7} \text{ m} \)
- Use the formula: \( v = \frac{c}{\lambda} \)
- Calculation: \( v = \frac{3 \times 10^8 \text{ m/s}}{4.25 \times 10^{-7} \text{ m}} = 7.06 \times 10^{14} \text{ Hz} \)
- Type of radiation: UV radiation
**9. Problem Statement:**
What wavelength (λ) of radiation has photons of energy \( E \) at \( 2.87 \times 10^{-16} \text{ J} \)?
**Solution Steps:**
- Use the formula: \( E = \frac{hc}{\lambda} \), solve for λ
- Calculation involves rearranging to find \( \lambda \)
**10. Problem Statement:**
A photon of visible light has a frequency (ν) of 4.3 x 10¹⁴ s
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