11. An experiment is required to resolve a 6 = 12 unit bias between two treatment groups with 90% power.The process noise is normal with standard deviation σ = 12.a. Determine the total number of observations required for the experiment if there is one variablewith two levels and the data are to be analyzed by the two-sample t test.b. Determine the total number of observations required if the experiment design is a 24 full factoraldesign.

To determine the total number of observations required for the experiment, we need to use the power…

Answered: 11. An experiment is required to…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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4. A study considered whether daily consumption of garlic could reduce tick bites. The study used a crossover design where half of the subjects used placebo first and garlic second and half the reverse. The authors described garlic being more effective with 58 subjects and placebo being more effective with 47 subjects. Does this suggest a real difference between garlic and placebo, or are the results consistent with random variation? Complete parts a through d below. a. Identify the relevant variable and parameter. OA. The relevant variable is the population proportion, p, those for whom garlic is more effective than placebo. The parameter is whether garlic or placebo is more effective. B. The relevant variable is whether garlic or placebo is more effective, and the parameter is the population proportion, p, those for whom placebo is more effective than garlic. C. The relevant variable is whether garlic or placebo is more effective, and the parameter is the population proportion, p,…
Suppose IQ scores were obtained for 20 randomly selected sets of siblings. The 20 pairs of measurements yield x=101.22, y=102.45, r=0.916, P-value=0.000, and y=−8.44+1.1x, where x represents the IQ score of the older child. Find the best predicted value of y given that the older child has an IQ of 99? Use a significance level of 0.05.
Suppose IQ scores were obtained for 20 randomly selected sets of twins. The 20 pairs of measurements yield x= 99.11, y = 100.1, r=0.872, P-value = 0.000, and y = 7.99 +0.93x, where x represents the IQ score of the twin bom first. Find the best predicted value of y given that the twin born first has an IQ of 96? Use a significance level of 0.05. 1 Critical Values of the Pearson Correlation Coefficient r E Click the icon to view the critical values of the Pearson correlation coefficient r. The best predicted value of y is. Critical Values of the Pearson Correlation Coefficient r a = 0.01 NOTE: To test Ho: p=0 against H,: p#0, reject H, if the absolute value of r is greater than the critical value in the table. (Round to two decimal places as needed.) a = 0.05 4 0.950 0.990 0.878 0.959 0.811 0.917 0.754 0.875 0.834 0.798 0.765 0.735 0.708 8 0.707 9 0.666 10 0.632 11 0.602 0.576 0.553 12 0.684 13 0.661 0.641 0.623 0.606 14 0.532 0.514 15 16 17 0.497 0.482 0.468 0.456 0.444 0.590 0.575…
Snow avalanches can be a real problem for travelers in the western United States and Canada. A very common type of avalanche is called the slab avalanche. These have been studied extensively by David McClung, a professor of civil engineering at the University of British Columbia. Suppose slab avalanches studied in a region of Canada had an average thickness of u = 67 cm. The ski patrol at Vail, Colorado, is studying slab avalanches in its region. A random sample of avalanches in spring gave the following thicknesses (in cm). 59 51 76 38 65 54 49 62 68 55 64 67 63 74 65 79 (i) Use a calculator with sample mean and standard deviation keys to find x and s. (Round your answers to two decimal places.) X= cm S= cm (ii) Assume the slab thickness has an approximately normal distribution. Use a 1% level of significance to test the claim that the mean slab thickness in the Vail region is different from that in the region of Canada. (a) What is the level of significance? State the null and…
Suppose IQ scores were obtained for 20 randomly selected sets of siblings. The 20 pairs of measurements yield x = 99.37, y = 98.55, r=0.859, P-value = 0.000, and y = 10.94 +0.88x, where x represents the IQ score of the older child. Find the best predicted value of y given that the older child has an IQ of 105? Use a significance level of 0.05. 10CritPearson.pdf O A. 98.55 OB. 0.88 O C. 99.37 O D. 103.34
е. Sample region 6. Question: In a hypothesis test, what does the values of T(0) signify? a. Smallest level of significance for rejection of Null Hypothesis. b. Largest level of significance for rejection of Null Hypothesis. c. Smallest level of significance for acceptance of Null Hypothesis d. Largest level of significance for acceptance of Null Hypothesis 3
1. Develop 3 sigma level process control charts for monitoring weight of boxes that contain apples. You performed samplings over 5 weeks with sample size of 4 (n = 4). Draw variable control charts (mean and range). Calculate and show values for UCL, CL, and LCL using the factors provided in below table. Discuss your graphs and make your conclusion. Week1 Week2 Week3 Week4 Week5 week # of complaint Week complaints 1 1 1 7 2 2 2 6 20 21 21 24 30 3 Sample Size 8 n 2 3 4 5 10 15 20 25 3 3 21 20 23 21 20 4 7 A2 Control Limit Factor for Sample Mean 1.880 1.023 0.729 0.577 0.308 0.223 0.180 0.153 4 4 20 22 23 27 24 Factors for 3 Sigma level 5 2 D3 0 0 0 0 2. The number of monthly customer complaint at a hotel is monitored. Develop three sigma level control chart using the data below. Calculate and show values for UCL, CL, and LCL. Draw the control chart. Is everything under control? Discuss your conclusion. You will have to choose the proper control chart. 0.223 0.348 0.414 0.459 5 5 19 21 25…
4. Using traditional methods, it takes 101 hours to receive an advanced driving license. A new training technique using Computer Aided Instruction (CAI) has been proposed. A researcher used the technique on 90 students and observed that they had a mean of 102 hours. Assume the population variance is known to be 16. Is there evidence at the 0.05 level that the technique performs differently than the traditional method? Step 1. State the null and alternative hypotheses. Step 2. Find the value of the test statistic. Round your answer to two decimal places. Step 3. Specify if the test is one-tailed or two-tailed. Step 4. Find the �-value of the test statistic. Round your answer to four decimal places. Step 5. Identify the level of significance for the hypothesis test. Step 6. Make the decision to reject or fail to reject the null hypothesis
Getting an adequate amount of sleep can improve a variety of physiological functions, and it is known that the average number of hours that people sleep each night is normally distributed. A psychiatrist or a major research center takes an SRS of 25 emotionally disturbed patients and records the average amount of sleep that each gets on a typical night. He summarizes the data and finds that Xbar=6.90 and S= 0.878. What sample size would the researcher need to use in order to decrease the margin of error of a 95% confidence interval to +-0.20 hours?
Suppose IQ scores were obtained for 20 randomly selected sets of couples. The 20 pairs of measurements yield x = 101.02, y = 100.75, r = 0.852, P-value = 0.000, and y = 5.93 + 0.94x, where x represents the IQ score of the husband. Find the best predicted value of y given that the husband has an lQ of 100? Use a significance level of 0.05. %3D Click the icon to view the critical values of the Pearson correlation coefficient r. The best predicted value of y is Critical values of the pearson correlation coefficient r (Round to two decimal places as needed.) Critical Values of the Pearson Correlation Coefficient r X = 0.05 a = 0.01 INOTE: To test Ho: p=0 n Jagainst H,: p+0, reject Ho if the absolute value of r is greater than the critical value in the table. 4 0.950 0.990 0.878 0.959 0.811 0.917 7 0.754 0.875 0.707 0.834 0.666 0.798 10 0.632 0.765 11 0.602 0.735 12 0.576 0.708 13 0.553 0.684 14 0.532 0.661 15 0.514 0.641 16 0.497 0.623 17 0.482 0.606 18 0.468 0.590 19 0.456 0.575 20 0.444…
Plz answer both questions 01) 3. In a larger-scale replication study, 60 subjects were randomly assigned to one of 3 treatment conditions (0 ml., 5 ml., or 10 ml. of melatonin). After treatment, the total sum of squares was found to be 6504.75. In addition, 32% of the variance between the groups' measured depression could be accounted for by the different dosages of melatonin they had been administered. Does this study show significant differences between the groups' mean depression scores (α ≤ .025) 4. Forty eight subjects were randomly assigned to one of 4 treatment conditions in a study of different methods of coping with statistics exam anxiety. After the experiment, 12 subjects remained in group 1, 8 in group 2, 10 in group 3, and 10 in group 4. The mean anxiety score of group 1 was found to be 5.5 points higher than the mean of group 2, 3.5 points higher than the mean of group 3, 5.3 points higher than the mean of group 4, and 3.3 points higher than the grand mean.…

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