Homework Help is Here – Start Your Trial Now!
Math
Probability
(11) Use the commonly stated form of Chebyshev's inequality to find an upper bound to P(X > 300) when X ~ - Poisson(10).

(11) Use the commonly stated form of Chebyshev's inequality to find an upper bound to P(X > 300) when X ~ - Poisson(10).

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
See similar textbooks
icon
Related questions
Question
(11) Use the commonly stated form of Chebyshev's inequality to find an upper bound to P(X > 300) when X - Poisson(10). (a) Note that P(X > 300) = P(X > 300) + P(X< -300), since P(X < -280) = 0. So, we have Std(X) V10 P(X > 300) = P(|X| > 300) < 0.010540925. 300 300 (b) Note that P(X > 300) = P(X > 300) + P(X< -300), since P(X < -280) = 0. So, we have Var(X) 10 P(X > 300) = P(|X|> 300)< 0.00011111. 3002 3002 (c) Cannot be done, since Chebyshev's inequality can only be applied when two sided tail probabilities are sought. (d) Note that P(|X – 10| > 290) = P(X > 300) + P(X < -280), since P(X < -280) = 0. So, we have Var(X) 10 P(X > 300) = P(|X – 10| > 290) < 0.000118906. 2902 2902 (e) None of the above. The correct proof is (а) (b) (c) (d) (e) N/A (Select One)
Transcribed Image Text:(11) Use the commonly stated form of Chebyshev's inequality to find an upper bound to P(X > 300) when X - Poisson(10). (a) Note that P(X > 300) = P(X > 300) + P(X< -300), since P(X < -280) = 0. So, we have Std(X) V10 P(X > 300) = P(|X| > 300) < 0.010540925. 300 300 (b) Note that P(X > 300) = P(X > 300) + P(X< -300), since P(X < -280) = 0. So, we have Var(X) 10 P(X > 300) = P(|X|> 300)< 0.00011111. 3002 3002 (c) Cannot be done, since Chebyshev's inequality can only be applied when two sided tail probabilities are sought. (d) Note that P(|X – 10| > 290) = P(X > 300) + P(X < -280), since P(X < -280) = 0. So, we have Var(X) 10 P(X > 300) = P(|X – 10| > 290) < 0.000118906. 2902 2902 (e) None of the above. The correct proof is (а) (b) (c) (d) (e) N/A (Select One)
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 1 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer