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(11 system of linear equations college production play of 360 tickets were sold the ticket prices were $8 the total income $ 10, 512 was 8 and 10 combined a) C) x+4 : 3320 8 x + 104 + 12 z = 360 X + y + 52 = 0 y + y + 2 = 360 3x + 10y +122=3320 x + y + 5z = d there were in 3 variables to solve a was > How many tickets were sold it $3.320 5 times the number of $12 tickets sold? b) x+y = 360 x +10y + 122 = 3320 x + y = 52 = 0 x +y + z = 33 20 3x + 10y + 12 2 = 340 xty - 520 Hickets of $8 of 10 0 of 12

(11 system of linear equations college production play of 360 tickets were sold the ticket prices were $8 the total income $ 10, 512 was 8 and 10 combined a) C) x+4 : 3320 8 x + 104 + 12 z = 360 X + y + 52 = 0 y + y + 2 = 360 3x + 10y +122=3320 x + y + 5z = d there were in 3 variables to solve a was > How many tickets were sold it $3.320 5 times the number of $12 tickets sold? b) x+y = 360 x +10y + 122 = 3320 x + y = 52 = 0 x +y + z = 33 20 3x + 10y + 12 2 = 340 xty - 520 Hickets of $8 of 10 0 of 12

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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the ticket prices were the total income was combined 8 and 10 a) C) JJJJJ 12 TO JJJJJ 7 11 system of linear equations in 3 variables to solve college production play of 360 tickets were sold $ 8, $10, $12 320 , нош many tickets were sold it times the number of $12 tickets sold? b) хту 8 * +4= 3320 8 x + 104 + 12 z = 360 = 0 X + 52 was 4 y + 5z y + y + 2 = 360 3 x + 10y +122= 3320 x + y + 5z = 0 There were GA d) = 360 x +10y + 12 2 = 3320 x + y - 52 = 0 x+y x + y + z = 33 20 8x + 10y + 12 2 = 340 xty - 5₂ = 0 fickets Hickets of $8 0 of 10 of 12
Transcribed Image Text:the ticket prices were the total income was combined 8 and 10 a) C) JJJJJ 12 TO JJJJJ 7 11 system of linear equations in 3 variables to solve college production play of 360 tickets were sold $ 8, $10, $12 320 , нош many tickets were sold it times the number of $12 tickets sold? b) хту 8 * +4= 3320 8 x + 104 + 12 z = 360 = 0 X + 52 was 4 y + 5z y + y + 2 = 360 3 x + 10y +122= 3320 x + y + 5z = 0 There were GA d) = 360 x +10y + 12 2 = 3320 x + y - 52 = 0 x+y x + y + z = 33 20 8x + 10y + 12 2 = 340 xty - 5₂ = 0 fickets Hickets of $8 0 of 10 of 12
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