Answer 11-15 Balancing Eguations WorksheetNAOH + KsPO41)NasPO4 +.KOH >MGF2+.LI2CO3 M9CO3 + LiF2)Pa+O2 → P2033)RbFBeF2 > Be(NO3)2+Ag4)RBNO3 +--AGNOS +Cu Cu(NO32+.5)CF4 +_ Br2 → _ CBr4 +_ F2H2SO4 +.6)--Cu(CN)2---7)HCN +.CusO4>.-Cs > CsF + GaPtS8)GaF3 +-9)Bas + PIF2->BaF2 +10)N2 + H2 >_ NH3--|1)Br2 NaBr +F2NaF +12)Pb(OH)2 +HCI >H20 +PbCl2--13)AIBr3 +-K2SO, >KBr +Al2(SO4)3--14)CH4 +02→CO2 +H20--15)NasPO4 +CaC2>NaCl +Cas(PO4)2-16)K+KCI--17)Al +HCI H2+AICI3--18)N2 +F2 _ NF3--19)SO2 +.LizSe>SSe2 +-Li2O-20)NH3 +H2SO4>(NHA)2SO4--

A balanced chemical equation states that the number of elements in the reactant side is equal to the…

Answered: 11) NaF + Br2 → NaBr + F2 - 12) -…

11) NaF + Br2 → NaBr + F2 - 12) - Pb(OH)2+ __HCI → H20 + PbCl2 - - 13) AIBR3 + K2SSO, > KBr + Al2(SO4)3 - - - 14) CH4 + 02→_CO2 + H20 - 15) NasPO4 + CaC2 > NaCl + Cas(PO4)2 -

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Answer 11-15

Balancing Eguations Worksheet
NAOH + KsPO4
1)
NasPO4 +.
KOH >
MGF2+.
LI2CO3 M9CO3 + LiF
2)
Pa+
O2 → P203
3)
RbF
BeF2 > Be(NO3)2+
Ag
4)
RBNO3 +
-
-
AGNOS +
Cu Cu(NO32+.
5)
CF4 +_ Br2 → _ CBr4 +_ F2
H2SO4 +.
6)
-
-
Cu(CN)2
---
7)
HCN +.
CusO4>.
-
Cs > CsF + Ga
PtS
8)
GaF3 +
-
9)
Bas + PIF2->
BaF2 +
10)
N2 + H2 >_ NH3
-
-
|
1)
Br2 NaBr +
F2
NaF +
12)
Pb(OH)2 +
HCI >
H20 +
PbCl2
-
-
13)
AIBr3 +
-K2SO, >
KBr +
Al2(SO4)3
-
-
14)
CH4 +
02→
CO2 +
H20
-
-
15)
NasPO4 +
CaC2>
NaCl +
Cas(PO4)2
-
16)
K+
KCI
-
-
17)
Al +
HCI H2+
AICI3
-
-
18)
N2 +
F2 _ NF3
-
-
19)
SO2 +.
LizSe>
SSe2 +
-
Li2O
-
20)
NH3 +
H2SO4>
(NHA)2SO4
-
-

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