11 [ f(x) dx = 8 and f(a)da 94 at g(x)dx= 10 and [ 94 h(x) dx = 23,

Calculus: Early Transcendentals
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Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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If 

\[
\int_{-94}^{-11} f(x) \, dx = 8
\]

and 

\[
\int_{-94}^{-11} g(x) \, dx = 10
\]

and 

\[
\int_{-94}^{-11} h(x) \, dx = 23,
\]

what does the following integral equal?

\[
\int_{-94}^{-11} [5f(x) + 2g(x) - h(x)] \, dx = \, \boxed{}
\] 

**Explanation:**

To solve the integral 

\[
\int_{-94}^{-11} [5f(x) + 2g(x) - h(x)] \, dx,
\]

we can use the linearity property of integrals. This allows us to separate the integral into individual components:

\[
= 5 \int_{-94}^{-11} f(x) \, dx + 2 \int_{-94}^{-11} g(x) \, dx - \int_{-94}^{-11} h(x) \, dx
\]

Substitute the given values:

\[
= 5(8) + 2(10) - 23
\]

\[
= 40 + 20 - 23
\]

\[
= 37
\]

So, the value of the integral is \(\boxed{37}\).
Transcribed Image Text:If \[ \int_{-94}^{-11} f(x) \, dx = 8 \] and \[ \int_{-94}^{-11} g(x) \, dx = 10 \] and \[ \int_{-94}^{-11} h(x) \, dx = 23, \] what does the following integral equal? \[ \int_{-94}^{-11} [5f(x) + 2g(x) - h(x)] \, dx = \, \boxed{} \] **Explanation:** To solve the integral \[ \int_{-94}^{-11} [5f(x) + 2g(x) - h(x)] \, dx, \] we can use the linearity property of integrals. This allows us to separate the integral into individual components: \[ = 5 \int_{-94}^{-11} f(x) \, dx + 2 \int_{-94}^{-11} g(x) \, dx - \int_{-94}^{-11} h(x) \, dx \] Substitute the given values: \[ = 5(8) + 2(10) - 23 \] \[ = 40 + 20 - 23 \] \[ = 37 \] So, the value of the integral is \(\boxed{37}\).
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