10x1 + 2x2 + 3x3 = 23 2x1- 10x2 +3x3 = -9 -X1-X2+5x3 = 12 What is the x2 for the third iteration when the equation is calculated using the Jacobi %3D %3D iteration method? The starting point O A) 2.092 B) -2.837 C) 1.345 O D) 3.1783 E) 3.083

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A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.