10kN Cut A: 10KN 10kN 2) Find the shear force and bending moment at the sections where marked. 15 KN Cut B: 10kN 0M M Ar Cut C: 10kN Cut D: 15kN 3m 3m 3m 3 m ΤΣΕ -0 anti-clockwise M = 0 → M=-10 Axif Ax→0 15kN BIC 9m M M 10kN-S=0 S= +10 kN ↓ 6 m -[10kNxAx]-M=0 M=0 ΑΣΕ, = 0 anti-clockwise M =0 -[10kVx3m]-M=0 > M=-30kN.m → M=30kN.m 10kN-S=0 →S +10 kN ↓ ΣΕ=0 = 10kN-15kN-S=0 S = 5 kN ↑ anti-clockwise M =0 anti-clockwiseM => M = 60kN.m M=-30kNmM=30kN.m S-5 kN -[10kVx3m]-M=0 10 10kV-15kN-S=0 S-5 kN MS= 5 kN 5kN =0 ⇒ -[10kNx3m]+[15kNx6m]-M = 0
10kN Cut A: 10KN 10kN 2) Find the shear force and bending moment at the sections where marked. 15 KN Cut B: 10kN 0M M Ar Cut C: 10kN Cut D: 15kN 3m 3m 3m 3 m ΤΣΕ -0 anti-clockwise M = 0 → M=-10 Axif Ax→0 15kN BIC 9m M M 10kN-S=0 S= +10 kN ↓ 6 m -[10kNxAx]-M=0 M=0 ΑΣΕ, = 0 anti-clockwise M =0 -[10kVx3m]-M=0 > M=-30kN.m → M=30kN.m 10kN-S=0 →S +10 kN ↓ ΣΕ=0 = 10kN-15kN-S=0 S = 5 kN ↑ anti-clockwise M =0 anti-clockwiseM => M = 60kN.m M=-30kNmM=30kN.m S-5 kN -[10kVx3m]-M=0 10 10kV-15kN-S=0 S-5 kN MS= 5 kN 5kN =0 ⇒ -[10kNx3m]+[15kNx6m]-M = 0
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
based on my calculation draw a shear force and bending moment digram
![10kN
Cut A:
10KN
10kN
2) Find the shear force and bending moment at the sections where marked.
15 KN
Cut B:
10kN
"(to
Ar
Cut C:
10kN
Cut D:
15kN
3m
3m
3m
3 m
15kN
BIC
ΤΣΕ -0
anti-clockwise M =0 → -[10kNxAx] - M=0
⇒ M=-10 Axif Ax0M=0
9m
M
M
10kN-S=0
6 m
S=+10 kN ↓
ΑΣΕ, = 0
anti-clockwise M =0
> M=-30kN.m → M=30kN.m
10kN-S=0
anti-clockwise M
M = 60kNm
S +10 kN ↓
-[10kVx3m]-M=0
ΣΕ=0 = 10kN-15kN-S=0 ⇒S= -5 kN
S= 5 kN ↑
anti-clockwise M =0 -[10kVx3m]-M=0
M=-30kNmM=30kN.m
TIF 010kN-15kN-S=0
MS= 5 kN
S-5 kN
5kN
=0 ⇒ -[10kNx3m]+[15kNx6m]-M=0](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6560095e-4f1a-4298-9204-210334fdfd03%2Fbf9eddd2-8b01-4383-bb08-76697c3d4906%2Fv265h3p_processed.jpeg&w=3840&q=75)
Transcribed Image Text:10kN
Cut A:
10KN
10kN
2) Find the shear force and bending moment at the sections where marked.
15 KN
Cut B:
10kN
"(to
Ar
Cut C:
10kN
Cut D:
15kN
3m
3m
3m
3 m
15kN
BIC
ΤΣΕ -0
anti-clockwise M =0 → -[10kNxAx] - M=0
⇒ M=-10 Axif Ax0M=0
9m
M
M
10kN-S=0
6 m
S=+10 kN ↓
ΑΣΕ, = 0
anti-clockwise M =0
> M=-30kN.m → M=30kN.m
10kN-S=0
anti-clockwise M
M = 60kNm
S +10 kN ↓
-[10kVx3m]-M=0
ΣΕ=0 = 10kN-15kN-S=0 ⇒S= -5 kN
S= 5 kN ↑
anti-clockwise M =0 -[10kVx3m]-M=0
M=-30kNmM=30kN.m
TIF 010kN-15kN-S=0
MS= 5 kN
S-5 kN
5kN
=0 ⇒ -[10kNx3m]+[15kNx6m]-M=0
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