10cos(1000t + 30°)V iL (t) 6mH vc(t) 1/2mF For the above circuit, use phasor domain analysis techniques to find i (t) and vclt). It is known that the solution for each has the following form iL(t) = A cos(1000t + B) Amps and vct) = C cos(1000r + D) Volts Where A and C are both positive and both B and Dare in degrees. Match the values accordingly. NOTE: Capacitance is 0.5x103 F and Inductance is 6 x 10 3 H v A= a. -26.3° V B= b. 1.5 v C= 1.6 v D= d. 1.3 e. 38.2° f. -20.2° g. 33.4° h. 5.5 4.5 j. 3.7 k. 1.1 1. 44,1° m. 2.7 n. -41.6° ll

Introductory Circuit Analysis (13th Edition)
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Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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10cos(1000t + 30°)V
IL (t)
6mH
vc(t)
1/2mF
For the above circuit, use phasor domain analysis techniques to find ij (t) and vc(t). It is known that the solution for each has
the following form
iL (t) = A cos(1000t + B) Amps
and
vclt) = C cos(1000t + D) Volts
Where A and C are both positive and both B and D are in degrees.
Match the values accordingly.
NOTE: Capacitance is 0.5x103 F and Inductance is 6 x 10-3 H
A=
a.
-26.30
B=
b. 1.5
C. 1.6
DD
d. 1.3
e. 38,2°
f.
-20.2°
g. -33.4°
h. 5.5
i. 4,5
j. 3.7
k. 1.1
1. 44.1°
m. 2.7
n. 41.6°
> > > >
Transcribed Image Text:10cos(1000t + 30°)V IL (t) 6mH vc(t) 1/2mF For the above circuit, use phasor domain analysis techniques to find ij (t) and vc(t). It is known that the solution for each has the following form iL (t) = A cos(1000t + B) Amps and vclt) = C cos(1000t + D) Volts Where A and C are both positive and both B and D are in degrees. Match the values accordingly. NOTE: Capacitance is 0.5x103 F and Inductance is 6 x 10-3 H A= a. -26.30 B= b. 1.5 C. 1.6 DD d. 1.3 e. 38,2° f. -20.2° g. -33.4° h. 5.5 i. 4,5 j. 3.7 k. 1.1 1. 44.1° m. 2.7 n. 41.6° > > > >
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