**109. Monochromatic light passes through materials a, b, and c. Rank the materials according to index of refraction, smallest 1st.**The image accompanying the text shows a diagram with three different materials labeled a, b, and c. A light ray is shown entering from the left, initially traveling through material a. Upon reaching the boundary with material b, the light ray bends, indicating a change in speed due to a different index of refraction. The ray continues through material b and then refracts again as it enters material c. From the refraction behavior, material a is likely to have the smallest index of refraction, as the light refracts toward the normal when entering material b, which suggests b has a higher refractive index than a. Similarly, as the light ray moves into material c from b, it refracts again, indicating a change in index. These refraction angles can help deduce the relative indices based on Snell's Law.

We have been given three different mediums a, b & c with corresponding refractive index μa, μb & μc.We know that when the light beam passes from one medium to another medium it always bend towards the normal when the refractive index of the incident region is smaller than that of refraction region & vice versa. More the bending of the beam towards the normal, More will be the refractive index of the refraction region. Thus from the given question we can see that in material-c bending of light is greatest as compared to material-b. So the order of the refractive index is, μa < μb < μc

Answered: 109. Monochromatic light passes through…

109. Monochromatic light passes through materials a, b, and c. Rank the materials according to index of refraction, smallest 1* a