103. An inductor is connected to a 20.0-Hz power supply that produces a 50.0-V rms voltage. What inductance is needed to keep the maximum current in the circuit below 80.0 mA?

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Chapter1: Units, Trigonometry. And Vectors
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**Question 103**

An inductor is connected to a 20.0-Hz power supply that produces a 50.0-V rms voltage. What inductance is needed to keep the maximum current in the circuit below 80.0 mA?

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**Explanation:**

This problem involves calculating the inductance required to limit the maximum current in an AC circuit with a given frequency and voltage. The key concepts include understanding reactance in AC circuits and using the formula for inductive reactance, \( X_L = 2\pi fL \), where \( f \) is the frequency and \( L \) is the inductance. The given conditions are:

- Frequency (\( f \)) = 20.0 Hz
- RMS voltage (\( V \)) = 50.0 V
- Maximum current (\( I_{\text{max}} \)) = 80.0 mA = 0.080 A

To find \( L \), use Ohm's Law for AC circuits, \( V = I \times X_L \), and solve for \( L \).
Transcribed Image Text:**Question 103** An inductor is connected to a 20.0-Hz power supply that produces a 50.0-V rms voltage. What inductance is needed to keep the maximum current in the circuit below 80.0 mA? --- **Explanation:** This problem involves calculating the inductance required to limit the maximum current in an AC circuit with a given frequency and voltage. The key concepts include understanding reactance in AC circuits and using the formula for inductive reactance, \( X_L = 2\pi fL \), where \( f \) is the frequency and \( L \) is the inductance. The given conditions are: - Frequency (\( f \)) = 20.0 Hz - RMS voltage (\( V \)) = 50.0 V - Maximum current (\( I_{\text{max}} \)) = 80.0 mA = 0.080 A To find \( L \), use Ohm's Law for AC circuits, \( V = I \times X_L \), and solve for \( L \).
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