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103 H.W :- the simply supported beam shown below carries the factored louded indicated. Using f'c = 20.7 N/mm ² and fy = 276 N/mm", design and detail the required. vertical stirrups W₁ = 100kN/m ₁Pu= lookN 700 Vc = d=630 $70 Vc = 126 + 350 Vudface of support = wuln, lu 2 100X6 + 10 = 350k 2 2 Sie bud 6 √ 2017 4 Vuo distanced from face. of support = 350 - wud Vud: 350-100x6+63 = 287kN * 350 KM x 350 X630 3m 3m * 6m (clear span) = 167.2KN 1000 Uc= 0.75X 167.2 = 125.4 KN 1/2 $ U² = 1/2 x 125.4 = 62.7 KN KN 5.F.D Sok

103 H.W :- the simply supported beam shown below carries the factored louded indicated. Using f'c = 20.7 N/mm ² and fy = 276 N/mm", design and detail the required. vertical stirrups W₁ = 100kN/m ₁Pu= lookN 700 Vc = d=630 $70 Vc = 126 + 350 Vudface of support = wuln, lu 2 100X6 + 10 = 350k 2 2 Sie bud 6 √ 2017 4 Vuo distanced from face. of support = 350 - wud Vud: 350-100x6+63 = 287kN * 350 KM x 350 X630 3m 3m * 6m (clear span) = 167.2KN 1000 Uc= 0.75X 167.2 = 125.4 KN 1/2 $ U² = 1/2 x 125.4 = 62.7 KN KN 5.F.D Sok

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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H.W :- 103 the simply supported beam shown below carries the factored louded indicated. Using f'c = 20.7 N/mm² and fy = 276 N/mm", design and detail the required vertical stirrups W₁ = 100kN/m ₁Pu= lookN 700 Vc = |d=630 $70 Vc = 126 + 350 Vudface of support = wuln, lu 2 100X6 + 10 = 350k 2 2 Sie bud 6 √ 2017 Vuo distanced from face. of support = 350 - wud Vud: 350-100x6+63 = 287 kN 4 * x 350 X630 350 KM ( ( 3m 3m 6m (clear span), =167.2KN 1000 Uc= 0.75X 167.2 = 125.4 KN // $U = = x 125.4 = 62.7 KN 2 52 Sok
Transcribed Image Text:H.W :- 103 the simply supported beam shown below carries the factored louded indicated. Using f'c = 20.7 N/mm² and fy = 276 N/mm", design and detail the required vertical stirrups W₁ = 100kN/m ₁Pu= lookN 700 Vc = |d=630 $70 Vc = 126 + 350 Vudface of support = wuln, lu 2 100X6 + 10 = 350k 2 2 Sie bud 6 √ 2017 Vuo distanced from face. of support = 350 - wud Vud: 350-100x6+63 = 287 kN 4 * x 350 X630 350 KM ( ( 3m 3m 6m (clear span), =167.2KN 1000 Uc= 0.75X 167.2 = 125.4 KN // $U = = x 125.4 = 62.7 KN 2 52 Sok
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