102 4000 100 80 60 40 20 2089 IR Spectrum (quid fam) % of base peak 3000 63 65 83 40 80 13C NMR Spectrum (50.0 MHz. CDCI, solution) proton coupled proton decoupled 200 ¹H NMR Spectrum (200 MHz. CDCI, solution) 10 9 8 2000 V (cm¹) M 98/100/102 120 m/e 160 160 7 m 1600 200 120 1200 6.0 5.8 ppm I 6 800 Mass Spectrum 240 680 C2H4Cl2 280 expansions سلللم solvent 1 L 80 1 22 2.0 ppm 5 4 Problem 13 No significant UV absorption above 220 nm 3 40 2 119 08 (ppm) TMS 1 1 1 0 8 (ppm) -

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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What is the IR and HNMRAndCNMR and mass in this example explain
102
4000
100
80
60
40
20
2089
IR Spectrum
(liquid fam)
wwww.
3000
63
65
83
40 80
13C NMR Spectrum
(50.0 MHz. CDCI, solution)
proton coupled
proton decoupled
200
¹H NMR Spectrum
(200 MHz. CDCI, solution)
10
9
8
2000
v (cm¹)
M
98/100/102
120 160
m/e
160
1
7
mar
689
1600
1200
200
120
800
Mass Spectrum
6.0 5.8 ppm
6
C2H4Cl2
240 280
expansions
solvent
1
80
22 20 ppm
5 4
Problem 13
No significant UV
absorption above 220 nm
3
40
2
08 (ppm)
TMS
1
1
119
1
1
0
8 (ppm)
--
Transcribed Image Text:102 4000 100 80 60 40 20 2089 IR Spectrum (liquid fam) wwww. 3000 63 65 83 40 80 13C NMR Spectrum (50.0 MHz. CDCI, solution) proton coupled proton decoupled 200 ¹H NMR Spectrum (200 MHz. CDCI, solution) 10 9 8 2000 v (cm¹) M 98/100/102 120 160 m/e 160 1 7 mar 689 1600 1200 200 120 800 Mass Spectrum 6.0 5.8 ppm 6 C2H4Cl2 240 280 expansions solvent 1 80 22 20 ppm 5 4 Problem 13 No significant UV absorption above 220 nm 3 40 2 08 (ppm) TMS 1 1 119 1 1 0 8 (ppm) --
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