1010 >e 1010 1010 >e 4 1011 1011 1011 > F1 F3 1110 1110- 1110 4 1101 1101 > 3 1101 4 4 S = 10 S = 11 S = 01 1000 1000 1000 1001 1001 1001 F4 F5 F6 0111 0111 0111 0110 >3 0110 0110 3 4. 4 S = 01 S = 10 S = 11 xnw 4-to-1 xnW T-01-t xnw 4-to-1 xnW 4-to-1 xnW xnW 4-to-1 4-to-1 1-1-1-1
1010 >e 1010 1010 >e 4 1011 1011 1011 > F1 F3 1110 1110- 1110 4 1101 1101 > 3 1101 4 4 S = 10 S = 11 S = 01 1000 1000 1000 1001 1001 1001 F4 F5 F6 0111 0111 0111 0110 >3 0110 0110 3 4. 4 S = 01 S = 10 S = 11 xnw 4-to-1 xnW T-01-t xnw 4-to-1 xnW 4-to-1 xnW xnW 4-to-1 4-to-1 1-1-1-1
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
Carefully study the following logic circuits and answer the next two questions.
The binary output at F2 is Blank 1 .
The binary output at F3 is Blank 2 .
![1010 >0
1010
1010
4
1011
1011
1011
4
F1
4
F2
4
F3
1110-
1110-
1110-
1101
1101
3
1101
4.
2
4
S = 10
S = 11
S = 01
1000
1000
1000
4
1001 -
1001
1001 –
F4
F5
4
F6
0111
0111
0111
4
4.
0110
0110
0110
4
4
S = 01
S = 10
S = 11
4-to-1
xnW
4-to-1
4-to-1
/ O - N
4-to-1
xnW
4-to-1
xn
4-to-1
xnW](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F83ec105c-8933-4446-9859-6e38082f1c16%2F2541a2ac-5f6f-4b73-a459-2474fe602380%2Fsj9jf7d_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1010 >0
1010
1010
4
1011
1011
1011
4
F1
4
F2
4
F3
1110-
1110-
1110-
1101
1101
3
1101
4.
2
4
S = 10
S = 11
S = 01
1000
1000
1000
4
1001 -
1001
1001 –
F4
F5
4
F6
0111
0111
0111
4
4.
0110
0110
0110
4
4
S = 01
S = 10
S = 11
4-to-1
xnW
4-to-1
4-to-1
/ O - N
4-to-1
xnW
4-to-1
xn
4-to-1
xnW
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