**Problem Statement:**100.0 mL of a 0.755 M solution of KBr is diluted to 500.0 mL. What is the new concentration of the solution?---To find the new concentration after dilution, use the formula:\[ C_1V_1 = C_2V_2 \]Where:- \( C_1 \) is the initial concentration (0.755 M)- \( V_1 \) is the initial volume (100.0 mL)- \( C_2 \) is the final concentration (unknown)- \( V_2 \) is the final volume (500.0 mL)Rearrange the formula to solve for \( C_2 \):\[ C_2 = \frac{C_1V_1}{V_2} \]Substitute the known values:\[ C_2 = \frac{0.755 \, \text{M} \times 100.0 \, \text{mL}}{500.0 \, \text{mL}} \]\[ C_2 = \frac{75.5}{500.0} \]\[ C_2 = 0.151 \, \text{M} \]Therefore, the new concentration of the KBr solution is 0.151 M.

We have to calculate the new concentration of Solution.

Answered: 100.0 mL of a 0.755 M solution of KBr…

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100.0 mL of a 0.755 M solution of KBr is diluted to 500.0 mL. What is the new concentration of the solution?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

**Problem Statement:**

100.0 mL of a 0.755 M solution of KBr is diluted to 500.0 mL. What is the new concentration of the solution?

---

To find the new concentration after dilution, use the formula:

\[ C_1V_1 = C_2V_2 \]

Where:
- \( C_1 \) is the initial concentration (0.755 M)
- \( V_1 \) is the initial volume (100.0 mL)
- \( C_2 \) is the final concentration (unknown)
- \( V_2 \) is the final volume (500.0 mL)

Rearrange the formula to solve for \( C_2 \):

\[ C_2 = \frac{C_1V_1}{V_2} \]

Substitute the known values:

\[ C_2 = \frac{0.755 \, \text{M} \times 100.0 \, \text{mL}}{500.0 \, \text{mL}} \]

\[ C_2 = \frac{75.5}{500.0} \]

\[ C_2 = 0.151 \, \text{M} \]

Therefore, the new concentration of the KBr solution is 0.151 M.

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